This is a freezing point depression problem, so it will use the equation:
ΔT = i Kf<span> m
</span>
i = 1 (naphthalene does not dissociate further when dissolved)
Kf = 7.10 C/m (a constant for paradichlorobenzene, which you'd be given)
m = moles of solute / kg of solvent; moles of solute = 4.78 / 128.2 = 0.0373; kg of solvent = 0.032; m = 0.0373 / 0.032 = <span>1.166m
</span>ΔT = 1 x 7.10 x 1.166 = 8.279 C
This means the normal freezing point of pure paradichlorobenzene is decreased by 8.279 C; the normal freezing point (again, something you'd be given) is 53.5 C, so the new freezing point would be 53.5 - 8.279 = 45.221 C.
For the first question, the answer is D because C because alkanes have single bonds ( alkenes have double bonds).
For the second question, the prefix is pen.
Acids have a pH less than 7 (pH < 7)
Bases have a pH more than 7 (pH > 7)
A pH of 7 would be neutral
Hope this helped!
When a beta particle<span> is emitted from the </span>nucleus<span> the </span>nucleus<span> has one more proton and one less neutron. This means the </span>atomic<span> mass number remains unchanged and the </span>atomic<span> number increases by 1.
Best answer :
</span><span>b. the number of electrons in the atom increases by one as the beta particle leaves the nucleus and joins the valence electrons</span>
Answer:

Explanation:
Data:
I = 2.15 A
t = 8 min 24 s
T = 26.0 °C
V = 65.4 mL
p = 774.2 To
1. Write the equation for the half-reaction
2H₂O ⟶ O₂ + 4H⁺ + 4e⁻
2. Calculate the moles of oxygen
V = 0.0654 L
T = (26.0 + 273.15) K = 299.15 K

3. Calculate the moles of electrons

4. Calculate the number of coulombs
t = 8 min 24 s =504 s
Q = It = 504 s × 2.10 C·s⁻¹= 1058 C
5. Calculate the number of electrons

6. Calculate Avogadro's number
