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Vitek1552 [10]
4 years ago
15

2NO2(g) Equilibrium N2O4(g)

Chemistry
1 answer:
FrozenT [24]4 years ago
3 0

Answer:

h The rates of the forward and reverse reaction are equal.

Explanation:

The reaction takes place in a closed container . So both the reactant (NO₂) and product N₂O₄ are present in the reaction container. Under such conditions, the reaction reaches chemical equilibrium. At chemical equilibrium the rates of the forward and reverse reactions are equal. The concentration of the reactants and products remain constant at Chemical Equilbrium.

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What is the freezing point of a solution containing 4.78 grams naphthalene (molar mass = 128.2 g/mol) dissolved in 32.0 grams pa
tester [92]
This is a freezing point depression problem, so it will use the equation:

ΔT = i Kf<span> m
</span>
i = 1 (naphthalene does not dissociate further when dissolved)
Kf = 7.10 C/m (a constant for paradichlorobenzene, which you'd be given)
m = moles of solute / kg of solvent; moles of solute = 4.78 / 128.2 = 0.0373; kg of solvent = 0.032; m = 0.0373 / 0.032 = <span>1.166m

</span>ΔT = 1 x 7.10 x 1.166 = 8.279 C

This means the normal freezing point of pure paradichlorobenzene is decreased by 8.279 C; the normal freezing point (again, something you'd be given) is 53.5 C, so the new freezing point would be 53.5 - 8.279 = 45.221 C.
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4 years ago
Hydrogen and carbon atoms bonded with single bonds are called:
photoshop1234 [79]
For the first question, the answer is D because C because alkanes have single bonds ( alkenes have double bonds). For the second question, the prefix is pen.
3 0
4 years ago
What pH value can be assigned to acids and bases, respectively?
goldfiish [28.3K]
Acids have a pH less than 7 (pH < 7)
Bases have a pH more than 7 (pH > 7)
A pH of 7 would be neutral

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When a beta particle is released from the nucleus of an atom:
Anon25 [30]
When a beta particle<span> is emitted from the </span>nucleus<span> the </span>nucleus<span> has one more proton and one less neutron. This means the </span>atomic<span> mass number remains unchanged and the </span>atomic<span> number increases by 1.
Best answer :
</span><span>b. the number of electrons in the atom increases by one as the beta particle leaves the nucleus and joins the valence electrons</span>
6 0
3 years ago
Read 2 more answers
In a similar experiment, a current of 2.15 amps ran for 8 minutes and 24 seconds. The temperature of the water was 26.0°C. The v
lord [1]

Answer:

\boxed{6.08 \times 10^{23}}

Explanation:

Data:

I = 2.15 A

t = 8 min 24 s

T = 26.0 °C

V = 65.4 mL

p = 774.2 To

1. Write the equation for the half-reaction

2H₂O ⟶ O₂ + 4H⁺ + 4e⁻

2. Calculate the moles of oxygen

p = \text{774.2 To} \times \dfrac{\text{1 atm}}{\text{760 To}} = \text{1.0187 atm}

V = 0.0654 L

T = (26.0 + 273.15) K = 299.15 K

\begin{array}{rcl}pV& = & nRT\\1.0189 \times 0.0654 & = & n \times 0.08206 \times 299.15\\0.06662 & = & 24.55n\\\\n & = & \dfrac{0.06662}{24.55}\\\\n & = & 2.714 \times 10^{-3}\\\end{array}

3. Calculate the moles of electrons

\text{n} = \text{2.714 $\times 10^{-3}$ mol oxygen} \times \dfrac{\text{4 mol electrons}}{\text{ 1 mol ozygen}} = \text{ 0.01086 mol electrons}

4. Calculate the number of coulombs

t = 8 min 24 s =504 s

Q = It = 504 s × 2.10 C·s⁻¹= 1058 C

5. Calculate the number of electrons

\text{No. of electrons} = \text{1058 C} \times \dfrac{\text{1 electron}}{1.602 \times 10^{-19}\text{ C}} = 6.607 \times 10^{21}\text{ electrons}

6. Calculate Avogadro's number

N_{\text{A}} = \dfrac{6.607 \times 10^{21}}{0.01086} = \mathbf{6.08 \times 10^{23}}\\\\\text{The experimental value of Avogadro's number is } \boxed{\mathbf{6.08 \times 10^{23}}}

3 0
4 years ago
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