You are given an aqueous solution and are asked to analyze it for the presence (or absence) of Ag+(aq), Ca2+(aq), and/or Hg2+(aq
) ions. There are no other metal ions in the solution. You add aqueous hydrochloric acid (HCl) to the solution, and nothing appears to happen. You add aqueous sulfuric acid (H2SO4) to the solution, and a white precipitate forms. You remove (via filtration) the white precipitate, and then add aqueous hydrogen sulfide (H2S) to the solution that remains. A black precipitate forms. Based on these observations, which ions are present in the original solution? (a) Ag+(aq), Ca2+(aq), and Hg2+(aq) (b) only Ag+(aq) and Hg2+(aq) (c) only Ca2+(aq) and Hg2+(aq) (d) only Ag+(aq) and Ca2+(aq) (e) only Hg2+(aq)
<span>2.51 grams
You want to prepare 19.16 g of some solution which will have 13.1% of it's mass being sucrose. So we just need to perform some simple multiplication:
19.16g * 0.131 = 2.50996g
Rounding to 3 significant figures gives 2.51 g.</span>