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Dmitriy789 [7]
3 years ago
15

When a beta particle is released from the nucleus of an atom:

Chemistry
2 answers:
Travka [436]3 years ago
8 0

Answer: c. the mass number of the atom remains the same

Explanation:

General representation of an element is given as: _Z^A\textrm{X} where,

Z represents Atomic number

A represents Mass number

X represents the symbol of an element

Beta-decay: In this process, a neutron gets converted into a proton and an electron releasing a beta-particle. The beta particle released carries a charge of -1 units.  Thus the number of electrons

_Z^A\textrm{X}\rightarrow _{Z+1}^A\textrm{Y}+_{-1}^0\beta

Anon25 [30]3 years ago
6 0
When a beta particle<span> is emitted from the </span>nucleus<span> the </span>nucleus<span> has one more proton and one less neutron. This means the </span>atomic<span> mass number remains unchanged and the </span>atomic<span> number increases by 1.
Best answer :
</span><span>b. the number of electrons in the atom increases by one as the beta particle leaves the nucleus and joins the valence electrons</span>
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the half-life of silicon-32 is 710 years. if 100 grams is present now, how much will be present in 300 years?
umka2103 [35]

The amount of Silicon left after 300 years is 75g

It is given that the initial amount of Si is 100 times decay is 300 years and the half-life of Silicon is 710 years.

The radioactive decay formula is given by,

A = A₀ x 2^(-t/h);

where;

A is the resulting amount after t time, Ao is the initial amt (t=0),t is the time of decay, and h is the half-life of the substance.

On substituting the values from the given we get,

A = 100x2^(-300/710)

A = 100 x 0.746112347

A = 74.6112347 grams left after 300 yrs

Therefore, the number of grams of silicon left after 300 years is 74.6112347g. This value could be rounded off to 75 grams as in the whole number

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3 0
2 years ago
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3 years ago
What would be the mass of 9.03*10^21 molecules of hydrobromic acid
Fynjy0 [20]

Answer:

2.11 g hydrobromic acid (correct to 3SF)

Explanation:

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mass of C2H5BrO2 = 140.96g

Beginning with what we're given, 9.03*10^21 we then make a conversion by using Avegadro's number which is 6.02*10^23 per mole (Oct. 23 at 6:02 am is national mole day :) Then, we need to convert out of moles, 140.96g hydrombromic acid per mole.

It looks like this:

9.03*10^21 molecules • (1 mol C2H5BrO2 / 6.02*10^23 molecules) • (140g C2H5BrO2 / 1 mol) = 2.1144 g C2H5BrO2

3 0
3 years ago
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