Answer:
CO2 molecule is made up of Carbon (atomic mass =12) and oxygen (atomic mass=16).
So first finding the mass of 1 molecule of CO2 which is equals to
= mass of 1 carbon atom + masses of 2 oxygen atom, we get
= 12+(16*2)= 12+32= 44 a.m.u.
Now 1 molecule of CO2 has mass 44 amu so mass of 1 mole CO2 will be 44 grams.( 1 a.m.u.=1.6729*10^-33 grams. 1 mole = 6.022*10^23, so 44 a.m.u.=73.6076*10^-33 grams approx. For one mole CO2, 73.6076*10^-33*6.022*10^23 which is approximately equals to 44 grams. )
1 mole CO2= 44grams, so 2.5 moles = 44*2.5= 110 grams
So our answer is 110 grams
<span>ΔT for the first sample is the total samples final temp, minus the first sample's initial temp (47.9-22.5), so 25.4oC.
Calculating q for the first sample as 108g x 4.18 J/g C x 25.4oC = 11466.58 Joules
Figuring that since the first sample gained heat, the second sample must have provided the heat, so doing the calculation for the second sample, I used
q=mCΔT
11466.58 Joules = 65.1g x 4.18 J / g C x ΔT
11466.58/(65.1gx4.18)=ΔT
ΔT=42.14oC
So, since second sample lost heat, it's initial temperature was 90.04oC (47.9oC final temperature of mixture + 42.14oC ΔT of second sample).</span>
13 compared to 8.3.................................
Answer:
Sleep, behavior patterns, mental state, and job
Explanation:
Answer:
4.78 x 10^-11 J
Explanation:
A = 1.5 x 10^-4 m^2
d = 2 mm = 2 x 10^-3 m
V = 12 V
Let C be the capacitance of the capacitor
C = ε0 A / d
C = (8.854 x 10^-12 x 1.5 x 10^-4) / (2 x 10^-3)
C = 6.64 x 10^-13 F
Energy stored, U = 1/2 CV^2
U = 0.5 x 6.64 x 10^-13 x 12 x 12
U = 4.78 x 10^-11 J