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Leya [2.2K]
3 years ago
12

Which of the following statements can be concluded (deducted) from the parallel-axis theorem? The area moment of inertia of an a

rea about a noncentroidal axis is always less than that about a centroidal axis The area moment of inertia of an area about a noncentroidal axis is always greater than that about a centroidal axis The area moment of inertia of an area about a noncentroidal axis can be equal to that about a centroidal axis There is no relationship between the area moment of inertia of an area about a noncentroidal axis and that about a centroidal axis O None of the above
Physics
1 answer:
Ratling [72]3 years ago
5 0

Answer:

The statement that we can conclude is that the moment of inertial of any body about the centroidal axis is least of all the moment of inertia's of the body about any arbitrary axis in the body.

Explanation:

According to parallel axis theorem we have

I_{x}=I_{C.G}+Ax^{2}

Where

I_{x} is the moment of inertia about any arbitrary axis.

I_{C.G} is the moment of inertia about centroidal axis.

A is the area of section of which Moment of area is evaluated

'x' = is the distance between the axis and C.G

thus we conclude that I_{C.G} is least of all the moments.

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3 years ago
If the speed of sound in air is 343 m/s and the wavelength of this note is 2.62 m, what is the frequency of this C3 note? (Round
snow_lady [41]

Answer:

<em>The frequency of of the note = 131 Hz.</em>

Explanation:

<em>Frequency:</em><em> Frequency can be defined as the number of complete oscillation completed by a wave in one seconds. The S.I unit of frequency is Hertz ( Hz)</em>

v = λf ............................ Equation 1

Making f the subject of the equation,

f = v/λ .......................... Equation 2

Where v = Speed, λ = wavelength, f = frequency

<em>Given: v = 343 m/s, λ = 2.62 m.</em>

<em>Substituting these values into equation 2</em>

<em>f = 343/2.62</em>

<em>f = 131 Hz</em>

<em>Thus the frequency of of the note = 131 Hz.</em>

8 0
3 years ago
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Answer:

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Answer:

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Explanation:

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A charged particle accelerated to a velocity v enters the chamber of a mass spectrometer. The particle's velocity is perpendicul
gladu [14]

Answer:

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Explanation:

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In this problem, the velocity of the particle is perpendicular to the magnetic field, so

\theta=90^{\circ}

and the formula reduces to

F=qvB

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