1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Leya [2.2K]
3 years ago
12

Which of the following statements can be concluded (deducted) from the parallel-axis theorem? The area moment of inertia of an a

rea about a noncentroidal axis is always less than that about a centroidal axis The area moment of inertia of an area about a noncentroidal axis is always greater than that about a centroidal axis The area moment of inertia of an area about a noncentroidal axis can be equal to that about a centroidal axis There is no relationship between the area moment of inertia of an area about a noncentroidal axis and that about a centroidal axis O None of the above
Physics
1 answer:
Ratling [72]3 years ago
5 0

Answer:

The statement that we can conclude is that the moment of inertial of any body about the centroidal axis is least of all the moment of inertia's of the body about any arbitrary axis in the body.

Explanation:

According to parallel axis theorem we have

I_{x}=I_{C.G}+Ax^{2}

Where

I_{x} is the moment of inertia about any arbitrary axis.

I_{C.G} is the moment of inertia about centroidal axis.

A is the area of section of which Moment of area is evaluated

'x' = is the distance between the axis and C.G

thus we conclude that I_{C.G} is least of all the moments.

You might be interested in
A reconnaissance plane flies 605 km away from
kolezko [41]

Answer:

                      v_{avg}  = 355 m/s  

Explanation:

Distance = 605 km

Initial speed = v_{i} = 284 m/s

Final velocity = v_{f} = 426 m/s

Average speed = ?

There is two method two find average speed. In first method, using 3rd equation of motion, we find acceleration.

                        2as = v_{f}^{2}+v_{i}^{2}

Then using first equation of motion, we find time

                        v_{f} = v_{i}+at

Then using the formula of average velocity, we find average velocity

                         v_{avg}=\frac{total-distance}{total-time}

Second method is very simple

                                  v_{avg}=\frac{v_{f}+v_{i} }{2}

                                   v_{avg}=\frac{426+284}{2}

                                   v_{avg}  = 355 m/s      

8 0
3 years ago
Matter that emits no light at any wavelength is called
lorasvet [3.4K]

Matter that emits no light at any wavelength is called DARK MATTER.

4 0
3 years ago
Work done depends on
natima [27]

Answer:

C. Both force and displacement

Explanation:

Hope this helps

3 0
2 years ago
lonnie pitches a baseball of mass 0.02kg. The ball arrives at home plate with a speed of 40 m/s and is batted straight back to L
vodomira [7]

Answer:

I=2 kg.m/s

Explanation:

The impulse is defined as the change of momentum:

I=p_f-p_o\\I=m*v_f-m*v_o\\I=0.02kg*[(-60m/s)-40m/s]\\I=2kg.m/s

We took the final velocity as negative since it is going on the opposite direction of the intial motion of the ball.

8 0
3 years ago
mass of the planet is 12 times that of earth and its radius is thrice that of earth , then find the escape velocity on that plan
Over [174]

Answer:

The escape velocity on the planet is approximately 178.976 km/s

Explanation:

The escape velocity for Earth is therefore given as follows

The formula for escape velocity, v_e, for the planet is v_e = \sqrt{\dfrac{2 \cdot G \cdot m}{r} }

Where;

v_e = The escape velocity on the planet

G = The universal gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²

m = The mass of the planet = 12 × The mass of Earth, M_E

r = The radius of the planet = 3 × The radius of Earth, R_E

The escape velocity for Earth, v_e_E, is therefore given as follows;

v_e_E = \sqrt{\dfrac{2 \cdot G \cdot M_E}{R_E} }

\therefore v_e = \sqrt{\dfrac{2 \times G \times 12 \times M}{3 \times R} } =  \sqrt{\dfrac{2 \times G \times 4 \times M}{R} } = 16 \times \sqrt{\dfrac{2 \times G \times M}{R} } = 16 \times v_e_E

v_e = 16 × v_e_E

Given that the escape velocity for Earth, v_e_E ≈ 11,186 m/s, we have;

The escape velocity on the planet = v_e ≈ 16 × 11,186 ≈ 178976 m/s ≈ 178.976 km/s.

3 0
2 years ago
Other questions:
  • The pattern of repeating properties of elements revealed in the periodic table is known as the (Blank)
    15·2 answers
  • The charges Q1=Q and Q2=4Q that are a distance d apart, repel each other with a force of 1.60 N. What would be the force between
    14·1 answer
  • A student pushes a box across a rough horizontal floor. If the amount of work done by the student on the box is 100 J and the am
    15·1 answer
  • Two objects, A and B, each of mass o.22 kg, are moving at 0.34 m/s directly toward each other. What is the speed of Object A aft
    14·1 answer
  • If an object placed in a fluid experiences a buoyant force equal to the weight of the fluid it displaces, the object will float.
    12·1 answer
  • Peregrine falcons are the fastest birds in the world, reaching max- imum speeds of up to 320 km/h (88 m/s) during a hunting stoo
    12·1 answer
  • Work of 5 Joules is done in stretching a spring from its natural length to 19 cm beyond its natural length. What is the force (i
    11·1 answer
  • A person makes a cup of coffee by first placing a 200 W electric immersion heater in 0.32 kg
    6·1 answer
  • Yes or no
    11·1 answer
  • Which kind of inclined plane pushes up more? Steeper or flatter?
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!