Answer:
<h2><u>✍</u><u> </u><u>What is quantum physics?</u></h2>
- ➳ It's the physics that explains how everything works; the best description we have of the nature of the particles that make up matter and the forces with which they interact.
- Quantum physics underlies how atoms work, and so why chemistry and biology work as they do.
We are given the data for the angle of incidence and angle of refraction.
The first part of the problem is to plot the deviation and the angle of incidence. The minimum deviation is 37 with 65 degrees as the corresponding angle of incidence. The maximum deviation is 69 with a corresponding angle of incidence of 30 degrees. It is not advisable to use small values for the angle of incidence since it would result to a higher deviation from Snell's Law.
I believe it is very likely to bond with another atom because it only has 7 valence electrons in its outer shell. To complete the outer shell, to bond with another atom, it needs to have eight, or a multiple of 8 electrons in the outermost shell or valence shell. Hope this helps!
Answer:
wave changes its path from its initial direction so this phenomenon is known as Refraction of wave
Explanation:
When wave travels from one medium to other medium the due to change in the speed of the wave propagation it deviates from its initial path.
The deviation of the wave from its initial path is known as refraction of wave
Here we can see that wave incident on medium 1 with some angle with the boundary
Then it enters into other medium and then travels in other direction
So here wave changes its path from its initial direction so this phenomenon is known as Refraction of wave
Answer: the constant angular velocity of the arms is 86.1883 rad/sec
Explanation:
First we calculate the linear velocity of the single sprinkler;
Area of the nozzle = π/4 × d²
given that d = 8mm = 8 × 10⁻³
Area of the nozzle = π/4 × (8 × 10⁻³)²
A = 5.024 × 10⁻⁵ m²
Now total discharge is dived into 4 jets so discharge for single jet will be;
Q_single = Q / n = 0.006 / 4 = 1.5 × 10⁻³ m³/sec
So using continuity equation ;
Q_single = A × V_single
V_single = Q_single/A
we substitute
V_single = (1.5 × 10⁻³) / (5.024 × 10⁻⁵)
V_single = 29.8566 m/s
Now resolving the forces as shown in the second image,
Vt = Vcos30°
Vt = 29.8566 × cos30°
Vt = 25.8565 m/s
Finally we calculate the angular velocity;
Vt = rω
ω_single = Vt / r
from the given diagram, radius is 300mm = 0.3m
so we substitute
ω_single = 25.8565 / 0.3
ω_single = 86.1883 rad/sec
Therefore the constant angular velocity of the arms is 86.1883 rad/sec