Answer:The answer is when a metal plate is pressed against a fast spinning piece of steel hard enough to stop it. i know this because I just took a test and got this question and got it write
Explanation:
Answer:
B = 0.031T
Explanation:
Given n1 = 1000turn/m
i1 = 25A
μo = 4π ×10‐⁷ Wb/A•m
B1 = μo×i1×n1
B1 = 4π ×10‐⁷ × 25 × 1000 = 0.031T.
<span>14.79 m/s
At the top of the loop, there's 2 opposing forces. The centripetal force that's attempting to push the roller coaster away and the gravitational attraction. These 2 forces are in opposite directions and their sum is 0.80 mg where m = mass and g = gravitational attraction. So let's calculate the amount of centripetal force we need.
0.80 = F - 1.00
1.80 = F
So we need to have a centripetal force that's 1.8 times the local gravitational attraction which is 9.8 m/s^2. So
1.8 * 9.8 m/s^2 = 17.64 m/s^2
The formula for centripetal force is
F = mv^2/r
where
F = force
m = mass
v = velocity
r = radius
We can eliminate mass from the equation since the same mass is being affected by both the centripetal force and gravity. So:
F = v^2/r
17.64 m/s^2 = v^2/12.4 m
218.736 m^2/s^2 = v^2
14.78972616 m/s = v
So the velocity at the top of the loop (rounded to 2 decimal places) is 14.79 m/s.</span>
Explanation:
In order from highest to lowest energies the parts of electromagnetic spectrum are named as
Gamma rays,
X-rays,
ultraviolet radiation,
visible light,
infrared radiation,
and radio waves.
Microwaves are a subsections of radio waves. They are used in microwave ovens to heat the food items.
This is expected EM spectrum in field of science.
Answer:
the velocity of the point P located on the horizontal diameter of the wheel at t = 1.4 s is 
Explanation:
The free-body diagram below shows the interpretation of the question; from the diagram , the wheel that is rolling in a clockwise directio will have two velocities at point P;
- the peripheral velocity that is directed downward
along the y-axis
- the linear velocity
that is directed along the x-axis
Now;
Also,
where 
(angular velocity) = 
∴ the velocity of the point P located on the horizontal diameter of the wheel at t = 1.4 s is
