Answer:
1.95m/s
Explanation:
Please view the attached file for the detailed solution.
The following were the conversion factors used in order to express all quatities in SI units:
Answer:
C. tiny particles called charges flowing through the wires.
Explanation:
<h3> Hello!</h3>
An electric current is a stream of charged particles, such as electrons or ions, moving through an electrical conductor or space. It is measured as the net rate of flow of electric charge through a surface or into a control volume.
Hope it helps!
Answer:
a)6.34 x W/m²
b)1.37 x W/m²
c) see explanation.
Explanation:
a)The relation of intensity'I' of the radiation and area 'A' is given by:
I= P/A
where P= power of sunlight i.e 3.9 x J
and the area of the sun is given by,
A= 4π => 4π
A=6.15 x m²
= 3.9 x / 6.15 x =><u> 6.34 x </u><u>W/m²</u>
b) First determine the are of the sphere in order to determine intensity at the surface of the virtual space
A= 4π
Now R= 1.5 x m
A= 4π x 1.5 x =>2.83 x m²
The power that each square meter of Earths surface receives
= 3.9 x /2.83 x =><u>1.37 x </u><u> W/m²</u>
<u />
c) in part (b), by assuming the shape of the wavefront of the light emitted by the Sun is a spherical shape so each point has the same distance from the source i.e sun on the wavefront.
We can solve the problem by using conservation of energy.
In fact, initially the projectile has only kinetic energy, which is given by
where m is the projectile's mass while
is its initial velocity.
At the point of maximum height, the speed of the projectile is zero, so it only has gravitational potential energy which is equal to
where g is the gravitational acceleration and h is the maximum height of the projectile.
Since the energy must be conserved, we can equalize K and U to find the value of h: