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Lady_Fox [76]
3 years ago
9

1 what were the two classifications of motion, according to aristotle? a 2 according to aristotle, what kinds of motion required

no forces? a 3 what simple way of interpreting astronomical observations did copernicus advocate?
Physics
1 answer:
scoundrel [369]3 years ago
7 0

1. Answer;

Natural motion and violent motion

Explanation;

-Natural motion is the motion arising from the nature of an object. This motion does not require an external cause in order to occur. For example: Heavy bodies naturally move toward the center of the earth, therefore falling is a natural motion.

- Natural motion was determined by the nature of the object and how much of the four classical elements it contained. Violent motion is caused by external forces applied to the object.

2. Answer;

Natural motion

Explanation;

Natural motions are those motions that objects naturally did: objects on earth fell towards the center of the earth. Heavenly objects naturally moved in circles. Additionally, heavy bodies naturally move toward the center of the earth, therefore falling is a natural motion. The natural motion of objects is one of the characteristics of an object.

3. Answer;

To assume that Earth and the other planets rotate around the sun

Explanation;

-Copernicus proposed an alternative theory--that the Earth was a planet orbiting the Sun, and that all planets moved in circles, one inside the other. Mercury and Venus had the smallest circles, smaller than that of the Earth, and therefore their position in the sky was always near the Sun's.

-That made it easy to estimate their distances from the Sun in terms of the Earth-Sun distance.

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At the local playground, a 21-kg child sits on the right end of a horizontal teeter-totter, 1.8 m from the pivot point. On the l
Alja [10]

Answer:

Counterclockwise

Explanation:

We need to calculate the clocwkise and the counterclockwise torque.

The clockwise torque is the one generated by the child sitting on the right. This torque is given by:

M_C = F d

where

F=mg=(21 kg)(9.8 m/s^2)=205.8 N is the force exerted by the child (his weight)

d = 1.8 m is the distance from the pivot point

So, the clockwise torque is

M_C = (205.8 N)(1.8 m)=370.4 Nm

The counterclockwise torque is the one generated by the adult pushing on the left, and it is given by

M_A = F d

where

F = 151 N is the force applied

d = 3.0 m is the distance from the pivot

Substituting,

M_A = (151 N)(3.0 m)=453 Nm

So, the net torque is

M_A - M_C = 453 Nm - 370.4 Nm=82.6 Nm

And since the counterclockwise momentum is greater than the clockwise one, the teeter-totter will rotate counterclockwise.

3 0
3 years ago
Read 2 more answers
At the end of cylindrical rod of length l = 1 m and mass M = 1 kg rotating horizontaly along the vertical axis in its center wit
matrenka [14]

Answer:

w = 0.943 rad / s

Explanation:

For this problem we can use the law of conservation of angular momentum

       

Starting point. With the mouse in the center

            L₀ = I w₀

Where The moment of inertia (I) of a rod that rotates at one end is

         I = 1/3 M L²

Final point. When the mouse is at the end of the rod

          L_{f} = I w + m L² w

As the system is formed by the rod and the mouse, the forces during the movement are internal, therefore the angular momentum is conserved

        L₀ = L_{f}

        I w₀ = (I + m L²) w

        w = I / I + m L²) w₀

We substitute the moment of inertia

        w  = 1/3 M L² / (1/3 M + m) L²    w₀

        w = 1 / 3M / (M / 3 + m) w₀

We substitute the values

      w = 1/3 / (1/3 + 0.02) w₀

      w = 0.943 w₀

To finish the calculation the initial angular velocity value is needed, if we assume that this value is w₀ = 1 rad / s

        w = 0.943 rad / s

3 0
3 years ago
Which is a correct example of the principle of conservation of momentum? A) reversing of a car at a dead end B) conversion of ra
Hunter-Best [27]
I think the answer would be D.
3 0
3 years ago
Read 2 more answers
The half-life of nickel-63 is 100 years. If a sample of nickel-63 decays until 6.25% of the original sample remains, how much ti
a_sh-v [17]

Answer:

400 years

Explanation:

The equation that describes the decay of a radioactive sample is:

m(t)=m_0 (\frac{1}{2})^{t/t_{1/2}} (1)

where

m(t) is the amount of sample left at time t

m_0 is the initial amount of the sample

t_{1/2} is the half-life, which is the time taken for the sample to halve

In this problem we have:

t_{1/2}=100 y is the half-life of Nickel-63

After a time t, the amount of sample left is 6.25% of the original one, which means that

\frac{m(t)}{m_0}=\frac{6.25}{100}

So we can rewrite the equation (1) and solving for t to find the time:

\frac{6.25}{100}=(\frac{1}{2})^{t/t_{1/2}}\\\rightarrow \frac{t}{t_{1/2}}=4\\t=4t_{1/2}=4(100)=400 y

5 0
3 years ago
HURRRRRRRYYYYYYYYY
alex41 [277]

Answer:

I believe its C

Explanation:

Hope this helps!

-BB

3 0
3 years ago
Read 2 more answers
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