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vekshin1
3 years ago
6

Determine the inductance L of a 0.65-m-long air-filled solenoid 3.2 cm in diameter containing 8400 loops.

Physics
1 answer:
den301095 [7]3 years ago
5 0

Answer:

The inductance is  L  = 0.1097 \ H

Explanation:

From the question we are told that

  The  length is  l  =  0.65 \ m

   The  diameter is  d =  3.2 cm  = 0.032 \ m

    The  number of loops is  N  =  8400

Generally the radius is evaluated as

       r = \frac{ 0.032 }{2}  =  0.016 \ m

The  inductance is mathematically represented as

      L  =  \frac{ \mu_o  *  N^2  * A }{ l }

Here \mu_o is the permeability of free space with value  \mu_o   = 4\pi * 10^{-7} N/A^2

A is the cross-sectional area which is mathematically evaluated as

             A =  \pi  r^2

=>        A =  3.142 *  (0.016)^2

=>        A =  0.000804 \ m^2

 =>  L  =  \frac{   4\pi * 10^{-7} *  8400^2  * 0.000804  }{ 0.65 }

=>    L  = 0.1097 \ H

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