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3 years ago

How does the addition of a possible outlier on PLOT B affect the center of PLOT B relative to the center of PLOT A?

Mathematics

2 answers:

Otrada [13]3 years ago

8 0

Answer:

i think it would be b dont quote me on it

Step-by-step explanation:

tekilochka [14]3 years ago

6 0

Answer:THE ANSWER IS D

Step-by-step explanation:

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Help which one is the correct one

fredd [130]

B 1:5 is the correct answer

3 0

3 years ago

Greatfull in advance :)

nydimaria [60]

Answer:

160 m

Step-by-step explanation:

For the 15-deg angle, h is the opposite leg.

The hypotenuse is 628 m.

The trigonometry ratio that relates the opposite leg and the hypotenuse is the sine.

sin A = opp/hyp

$\sin 15^\circ = \dfrac{h}{628~m}$

$h = 628~m \times \sin 15^\circ$

$h = 162.54~m$

Rounded to 2 significant figures:

h = 160 m

5 0

3 years ago

Find the slope and the y-intercept of the graph of the linear equation.<br> 0 = 1 - 2y + 14x

yarga [219]

The slope is 7 and the y intercept is (0,1/2):)

6 0

3 years ago

Tell weather each equation has one, zero, or infinitely many solutions. -(2x + 2) - 1 = -x - (x + 3)

Anestetic [448]

$-(2x+2)-1=-x-(x+3) \\
-2x-2-1=-x-x-3 \\
-2x-3=-2x-3 \\
0=0 \\
always \ true \\ \\
\boxed{\hbox{infinitely many solutions}}$

7 0

3 years ago

If there is a nonmathematical symbol in the preceding expression, then your browser doesn't have the math symbol font. Please fo

horrorfan [7]

Complete Question

The complete question is shown on the first uploaded image

Answer:

$g(h(x)) = \sqrt[4]{x^2 + x +5} + 3$

$h(g(x)) = \sqrt{x} + 7\sqrt[4]{x} + 17$

$h(h(x)) = [x^2 + x + 5 ]^2 + x^2 + x + 10$

Step-by-step explanation:

From the question we are told that

$h(x) = x^2 + x + 5$

and

$g(x) = \sqrt[4]{x} + 3$

Considering first question

Now we are told g(h(x))

i.e

$g(h(x)) = [x^2 + x + 5 ]^{\frac{1}{4} } + 3$

=> $g(h(x)) = \sqrt[4]{x^2 + x +5} + 3$

Considering second question

Now we are told h(g(x))

i.e

$h(g(x)) = [x^{\frac{1}{4} } + 3]^2 + x^{\frac{1}{4} } + 3 + 5$

=> $h(g(x)) = x^{\frac{1}{2} } + 6x^{\frac{1}{4} } + 9+ x^{\frac{1}{4}} + 8$

=> $h(g(x)) = x^{\frac{1}{2}} + 7x^{\frac{1}{4}} + 17$

=> $h(g(x)) = \sqrt{x} + 7\sqrt[4]{x} + 17$

Considering third question

$h(h(x))= [x^2 + x + 5]^2 + [x^2 + x + 5 ] + 5$

=> $h(h(x)) = [x^2 + x + 5 ]^2 + x^2 + x + 10$

8 0

4 years ago