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2 years ago

Find the quotient. (2x^4-3x^3-6x^2+11x+8)/(x-2)

Mathematics

2 answers:

meriva2 years ago

6 0

Answer:

2x^3+x^2-4x+3+14/x-3 // Option B on edge

Step-by-step explanation:

Took the test

stiv31 [10]2 years ago

4 0

Since the remander is 0 the answer is 2x²+5x+2

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Decrease £16870 by 3% Give your answer rounded to 2 DP.

Liono4ka [1.6K]

Just do 16870 x .03 (3% as a decimal) and you'll get 506.10. Subtract that to 16870 and you'll get 16363.90.

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3 years ago

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Select the correct answer. what is this expression in simplified form? (6v2)(-3v5)

Roman55 [17]

Answer:

-180v^2

Step-by-step explanation:

multiply and calculate

3 0

2 years ago

Factor the trinomial. Factor out the GCF first.<br> 5x^2y - 30xy^2 - 35y^3

anzhelika [568]

Answer: $5x^2y - 30xy^2 - 35y^3=5y(x+y)(x-7y)$

Step-by-step explanation:

GCF = Greatest common factor.

For example: 6 is the GCF of 12 and 18.

The given expression: $5x^2y - 30xy^2 - 35y^3$

It can be written as

$5x^2y - (5\times6)x( y\times y) - (5\times7)(y^2\times y)$

Taking out common factor $5y$ , we get

$5y(x^2-6xy-7y^2)\\\\ =5y(x^2+xy-7xy-7y^2)\ \ [\because-6xy=xy-7xy]\\\\=5y(x(x+y)-7y(x+y))\\\\= 5y((x+y)(x-7y))\\\\=5y(x+y)(x-7y)$

Hence, $5x^2y - 30xy^2 - 35y^3=5y(x+y)(x-7y)$

3 0

3 years ago

Find the value of this expression if X = -1 and Y = -5 xy over -6

Thepotemich [5.8K]

$\frac{xy}{-6} = \frac{(-1)(-5)}{-6} = \frac{5}{-6} = -\frac{5}{6}$

4 0

2 years ago

A street light is at the top of a 25 ft pole. A 4 ft tall girl walks along a straight path away from the pole with a speed of 6

Burka [1]

Answer:

Tip of the shadow of the girl is moving with a rate of 7.14 feet per sec.

Step-by-step explanation:

Given : In the figure attached, Length of girl EC = 4 ft

Length of street light AB = 25 ft

Girl is moving away from the light with a speed = 6 ft per sec.

To Find : Rate ( $\frac{dw}{dt}$ ) of the tip (D) of the girl's shadow (BD) moving away from th

light.

Solution : Let the distance of the girl from the street light is = x feet

Length of the shadow CD is = y feet

Therefore, $\frac{dx}{dt}=6$ feet per sec. [Given]

In the figure attached, ΔAFE and ΔADE are similar.

By the property of similar triangles,

$\frac{x}{21}=\frac{x+y}{25}$

25x = 21(x + y)

25x = 21x + 21y

25x - 21x = 21y

4x = 21y

y = $\frac{4x}{21}$

Now we take the derivative on both the sides,

$\frac{dy}{dt}=\frac{4}{21}\times \frac{dx}{dt}$

= $\frac{4}{21}\times 6$

= $\frac{8}{7}$

≈ 1.14 ft per sec.

Since w = x + y

Therefore, $\frac{dw}{dt}= \frac{dx}{dt}+\frac{dy}{dt}$

$\frac{dw}{dt}=6+1.14$

= 7.14 ft per sec.

Therefore, tip of the shadow of the girl is moving with a rate of 7.14 feet per sec.

3 0

3 years ago