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Paha777 [63]
3 years ago
7

Which one of the following statements presents a condition required for the hardy-Weinberg principle to be in effect?

Biology
2 answers:
kodGreya [7K]3 years ago
8 0

Answer:

The correct answer is - random mating individuals pair by chance, not according to their genotypes or phenotypes.

Explanation:

Hardy-Weinberg equilibrium explains that if there are no other evolutionary influences on the population then the frequency of genotype in a specific population remains constant over generations.

The assumptions according to this principle are mention as follow -

-No natural selection.  

-no mutation.  

-The population size should be large.  

-There should be random mating  

-No gene flow.

The correct answer is - random mating individuals pair by chance, not according to their genotypes or phenotypes.

Aleks04 [339]3 years ago
5 0
The answer is random matting occurs!
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Answer:

See the answer below

Explanation:

Using the formula for calculating Chi square (X^2):

X^2  =  \frac{(O - E)^2}{E} where O = observed frequency and E = expected frequency.

The observed frequencies for the four phenotypes are 88, 62, 62, and 81 respectively.

For the expected frequency, the phenotypes are supposed to assort in 9:3:3:1 according to Mendel ratio.

Hence, expected frequencies are calculated as:

phenotype (1) = 9/16 x 293 = 164.81

phenotype (2) = 3/16 x 293 = 54.94

phenotype (3) = 3/16 x 293 = 54.94

phenotype (4) = 1/16 x 293 = 18.31

The X^2 is calculated thus:

Phenotype            O               E                             X^2

  1                          88            164.81            \frac{(88 - 164.81)^2}{164.81} = 35.80

  2                          62             54.94            \frac{(62 - 54.94)^2}{54.94} = 0.91

  3                           62             54.94              \frac{(62 - 54.94)^2}{54.94} = 0.91

  4                            81              18.31               \frac{(81 - 18.31)^2}{18.31} = 214.64

Total X^2 = 35.80 + 0.91 + 0.91 + 214.64 = 252.26

To the nearest tenth = 252

Degree of freedom = n - 1 = 4- 1 = 3

X^2 tabulated  = 7.815

<em>The calculated </em>X^2<em> exceeds the critical value, hence, the null hypothesis is rejected. The two genes did not assort independently.        </em>

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<span>It isn't genuine that in both gametogenesis occasions, which is known to be spermatogenesis in guys and oogenesis in females, may include meiosis with a similar number of gametes delivered when finished. Gametogenesis is known to be a procedure in which cells experience meiosis to shape gametes.</span>

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