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4 years ago

Round to the nearest hundredth : 3.2649

Mathematics

2 answers:

larisa [96]4 years ago

8 0

Answer:

3.26

Step-by-step explanation:

You round the second place after the decimal (6) by the place after it (4).

If the place after the number you need to round is a 5 or up, the decimal you round goes up one, if it is a 4 or lower it stays the same.

E.G. if 3.2649 was 3.2659 the hundreds would be rounded to 3.27. Since it's a 4, the six stays the same at 3.26.]

hope this helps (/o.o)/<3

Bas_tet [7]4 years ago

3 0

Answer:

3.26

Step-by-step explanation:

Rounding to the nearest hundredth means round to the nearest two decimal places.

To do this, all we need to look at is the 3rd decimal place.

Since 4 is not 5 or greater, that means we must round down, no matter how close it is to 5.

Therefore, the answer should just be 3.26

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Josh purchased a DVD for $10.80, before taxes. The price was after a 25% discount. What was the original price of the DVD?

andreev551 [17]

Answer:

2.70

Step-by-step explanation:

4 0

3 years ago

Help please with this only

Keith_Richards [23]

They are 7 units away!
Their cords are 5, -6 (bakery)
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3 years ago

Students in a class are asked to stand in ascending order according to their heights for the annual class photograph. Determine

horrorfan [7]

Answer:

The function in Python is as follows:

def heightChecker(heights):

expected = []

count = 0

for i in range(len(heights)):

expected.append(heights[i])

expected.sort()

for i in range(len(heights)):

if expected[i] != heights[i]:

count+=1

return count

Step-by-step explanation:

Required

Function to return the number of out of position students

See comment for complete question

This defines the function. It receives the heights as a parameter, from the main

def heightChecker(heights):

This initializes a list, (expected list)

expected = []

This initializes the count of out of position students

count = 0

This iterates through the original list

for i in range(len(heights)):

The list item is then appended to the expected list

expected.append(heights[i])

This sorts the expected list in ascending order

expected.sort()

This iterates through the original and the expected lists

for i in range(len(heights)):

If list elements at the same index are not the same, count is incremented by 1

if expected[i] != heights[i]:

count+=1

This returns count

return count

4 0

3 years ago

Suppose that prices of a certain model of a new home are normally distributed with a mean of $150,000. Use the 68-95-99.7 rule t

levacccp [35]

Answer:

68% of buyers paid between $147,700 and $152,300.

Step-by-step explanation:

We are given that prices of a certain model of a new home are normally distributed with a mean of $150,000.

Use the 68-95-99.7 rule to find the percentage of buyers who paid between $147,700 and $152,300 if the standard deviation is $2300.

Let X = prices of a certain model of a new home

SO, X ~ Normal( $\mu=150,000 ,\sigma=2,300$ )

The z score probability distribution for normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = population mean price = $150,000

$\sigma$ = standard deviation = $2,300

Now, according to 68-95-99.7 rule;

Around 68% of the values in a normal distribution lies between $\mu-\sigma$ and $\mu-\sigma$ .

Around 95% of the values occur between $\mu-2\sigma$ and $\mu+2\sigma$ .

Around 99.7% of the values occur between $\mu-3\sigma$ and $\mu+3\sigma$ .

So, firstly we will find the z scores for both the values given;

Z = $\frac{X-\mu}{\sigma}$ = $\frac{147,700-150,000}{2,300}$ = -1

Z = $\frac{X-\mu}{\sigma}$ = $\frac{152,300-150,000}{2,300}$ = 1

This indicates that we are in the category of between $\mu-\sigma$ and $\mu-\sigma$ .

SO, this represents that percentage of buyers who paid between $147,700 and $152,300 is 68%.

7 0

4 years ago

Need help as soon as possible please

valina [46]

80 - 9.38 = 70.62

41.54(.07) = 2.91

41.54 + 2.91 = 44.45

66(.07) = 4.62

66 + 4.62 = 70.62

With an $80 gift card, Stephanie can buy a sundress as long as the ticketed price is less than or equal to $66.00.

3 0

4 years ago

Read 2 more answers