integer userInput
integer i
integer mid
integer array(20) number
userInput = 1
for i = 0; userInput >= 0; i = i + 1
if number[i] > -1
userInput = Get next input
number[i] = userInput
i = i - 1
mid = i / 2
if i > 9
Put "Too many inputs" to output
elseif i % 2 == 0
Put number[mid - 1] to output
else
Put number[mid] to output
Answer:
i think you can layer it :)
Explanation:
nice drawing btw!
Answer:
num = float(input("Enter a number: "))
x =int(num)
y =float(num - x)
print(y)
Explanation:
It works I just did it!
CSS, or Cascading Style Sheets, will allow him to manipulate the looks.
It allows the technician to modify it
