Answer:
metric
hop count
Explanation:
Number of strings = (10, 2)×(8,3) = 2520
The number of possible combinations for taking two 0's is C(10, 2)
It remains 8 Positions
The number of possible combinations for taking three 1's is C(8,3)
So there remains 5 spots
screen - soft cloth
keyboard - paintbrush
answer is c
no need for explaination