Answer:
When <em>a scientist on Earth drops a hammer and a feather at the same time an astronaut on the moon drops a hammer and a feather, the result</em> expected is that <em>the hammer hits the ground before the feather on Earth, and the hammer and feather hit at the same time on the moon (option D).</em>
Explanation:
In the abscence of atmosphere (vacuum), the objects fall in free fall. This is, the only force acting on the objects is the gravitational pull, which is directed vertlcally downward.
Under such absecence of air, the equations that rules the motion are:
- V = Vo + gt
- d = Vo + gt² / 2
- Vf² = Vo² + 2gd
As you see, all those equations are independent of the mass and shape of the object. This explains why <em>when an astronaut on the moon drops a hammer and a feather at the same time</em>, <em>the hammer and feather hit at the same time on the moon</em>, a space body where the gravitational attraction is so small (approximately 1/6 of the gravitational acceleration on Earth) that does not retain atmosphere.
On the other hand, the air (atmosphere) present in Earth will exert a considerable drag force on the feather (given its shape and small mass), slowing it down, whereas, the effect of the air on the hammer is almost neglectable. In general and as an approximation, the motion of the heavy bodies that fall near the surface is ruled by the free fall equations shown above, so, <em>the result </em>that is<em> expected when a scientist on Earth drops a hammer and a feather at the same time is that the hammer hits the ground before the feather</em>.
Answer:- False.
Explanations:- One mole of any gas at STP occupies 1 volume of 22.4 L.
STP means standard temperature and pressure. Standard temperature is 273 K and standard pressure is 1 atm.
Here, in the statement the given temperature is 298 K which is not the standard temperature and so the volume of 1 mole of the gas will not be 22.4 L.
The volume could be calculated using ideal gas equation:
PV = nRT
R is the universal gas constant and it's value is .
let's plug in the values and calculate the volume for 1 mole of the gas:
V = 24.5 L
The volume for 1 mol of the gas at 298 K and 1 atm is 24.5 L and hence the statement is false.
The answer to this question should be Carbon dioxide.
To count the molar mass you need to add all the atoms weight that made up the compound. Carbon dioxide or CO2 is made of one carbon and two oxygen. Carbon molecular weight is 12. Oxygen molecular weight is 16. Then if you add them you will got: 12+ 2*16= 12 +32 = 44 g/mole.
Answer:
Explanation:
Hello there!
In this case, since the molality of a solution is calculated by dividing moles of solute by kilograms of solvent, it turns out firstly necessary for us to calculate the moles of methyl alcohol in 75.0 grams as shown below:
Then, the kilograms of water, 0.600 kg, and finally, the resulting molality:
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