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jarptica [38.1K]
3 years ago
15

Water boils at 100⁰C. What is the temperature on the Kelvin scale?

Chemistry
1 answer:
denis23 [38]3 years ago
7 0
The correct answer is D
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A fog over a lake. what two changes of state must occur to produce the fog? do the water molecules absorb or release energy duri
Zolol [24]
The water from the lake must first evaporate from the liquid state to the gaseous state and then condense in the air to form vapors.
The water molecules absorb energy while evaporating and release it when condensing. Their motion gets faster when they are evaporating and slows back down upon condensation.
3 0
3 years ago
Read 2 more answers
A gecko used its sticky feet to crawl from the bottom of a window to the top of
sp2606 [1]

Answer:

Decreased

Explanation:

You're faster when you go downhill than you are uphill.

8 0
3 years ago
When 33 g of CaO and 10 g of H2O react, how many grams of calcium hydroxide would you expect to be produced* Explain your answer
MrMuchimi

Answer:

41.44 g

Explanation:

First of all, we must put down the equation of the reaction;

CaO + H2O ----->Ca(OH)2

Number of moles of CaO = 33g/56 g/mol = 0.59 moles

Number of moles of H20 = 10g/18 g/mol = 0.56 moles

Since the reaction is in 1:1 mole ration, H2O is the limiting reactant

Hence;

mass of Ca(OH)2 produced = 0.56 moles * 74 g/mol = 41.44 g

7 0
3 years ago
Read 2 more answers
What we call "tin cans" are really iron cans coated with a thin layer of tin. The anode is a bar of tin and the cathode is the i
UNO [17]

Answer:

Fe (s) + Sn^{2+} (aq)\rightarrow Fe^{2+} (aq) + Sn (s)

Explanation:

Although the context is not clear, let's look at the oxidation and reduction processes that will take place in a Fe/Sn system.

The problem states that anode is a bar of thin. Anode is where the process of oxidation takes place. According to the abbreviation 'OILRIG', oxidation is loss, reduction is gain. Since oxidation occurs at anode, this is where loss of electrons takes place. That said, tin loses electrons to become tin cation:

Sn (s)\rightarrow Sn^{2+} (aq) + 2e^-

Similarly, iron is cathode. Cathode is where reduction takes place. Reduction is gain of electrons, this means iron cations gain electrons and produce iron metal:

Fe^{2+} (aq) + 2e^-\rightarrow Fe (s)

The net equation is then:

Sn (s) + Fe^{2+} (aq)\rightarrow Fe (s) + Sn^{2+} (aq)

However, this is not the case, as this is not a spontaneous reaction, as iron metal is more reactive than tin metal, and this is how the coating takes place. This implies that actually anode is iron and cathode is tin:

Actual anode half-equation:

Fe (s)\rightarrow Fe^{2+} (aq) + 2e^-

Actual cathode half-equation:

Sn^{2+} (aq) + 2e^-\rightarrow Sn (s)

Actual net reaction:

Fe (s) + Sn^{2+} (aq)\rightarrow Fe^{2+} (aq) + Sn (s)

6 0
3 years ago
FIND THE RATIO BY MASS OF THE COMBINING ELEMENTS IN THE FOLLOWING COMPOUNDS
boyakko [2]
The given compound is Aluminum sulfate, Al2(SO4)3:

Molar masses:

Aluminum = 27 g/mol
Sulfur = 32 g/mol
Oxygen = 16 g/mol

The total molar mass is 342 g/mol
The ratio by mass of the elements:

Aluminum = 27*2/342 
                  = 0.16
Sulfur = (32*3)/342
           = 0.28
Oxygen = (16*12)/342
              = 0.56
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5 0
3 years ago
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