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3 years ago

Water boils at 100⁰C. What is the temperature on the Kelvin scale?

Chemistry

1 answer:

denis23 [38]3 years ago

7 0

The correct answer is D

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How many grams of NaNO3 would have to be added to 100. grams of water at 45°C to make a saturated solution of this salt? 1. 100.

denis-greek [22]

Answer:

2. 110.

Explanation:

Kindly find the attached image.

From the solubility curve, you can find that at 45°C to make a saturated solution of this salt, you should add 110 g of NaNO₃.

So, the right choice: 2. 110.

4 0

4 years ago

Copper (Cu) is often used for electrical wiring and cooking pans. However, iron (Fe) is much more common on Earth than copper. W

Paha777 [63]

Copper is better at conducting electricity than iron.

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3 years ago

What are steps to solving stoichiomerty problems?

Arada [10]

<span>Balance the equation.
Convert units of a given substance to moles.
Using the mole ratio, calculate the moles of substance yielded by the reaction.
<span>Convert moles of wanted substance to desired units.</span></span>

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3 years ago

Tides are the rise and fall of surface levels of Earth's ocean water caused by the gravitational effects of which two celestial

NeTakaya

Answer:

Explanation:

Because the gravitational pull of the moon is weaker on the far side of the Earth, inertia wins, the ocean bulges out and high tide occurs.

hope it helps:)

4 0

3 years ago

Read 2 more answers

How many milliliters o a suspension base must be mixed with 250 mL o a paroxetine (PAXIL) oral suspension, 10 mg/5 mL, to change

Maksim231197 [3]

Answer : The suspension base added will be, 250 mL

Explanation :

As we are given that the initial concentration of solution is, 10 mg/5mL or we can say that 2 mg/mL.

Volume of solution = 250 mL

First we have to determine the mass of PAXIL.

As, 1 mL of solution contain mass of PAXIL = 2 mg

So, 250 mL of solution contain mass of PAXIL = $250\times 2=500mg$

Now we have to determine the final solution required.

As we are given the final concentration of solution is, 0.1 % w/v that means 0.1 g in 100 mL of solution.

Concentration of solution = $\frac{0.1g}{100mL}=\frac{0.1\times 1000mg}{100mL}=\frac{100mg}{100mL}=\frac{1mg}{mL}$

Let the 'x' mL of the suspension base is added. So, the ratio of mass and volume will be:

$\frac{500mg}{(x+250)mL}=\frac{1mg}{1mL}$

$x=250mL$

Thus, the suspension base added will be, 250 mL

4 0

3 years ago