Answer:
-24
Step-by-step explanation:
Answer:
from now on don't ask same qn two times or more it would be waste of your points
got it??
Answer:
= -√6
Step-by-step explanation:
1) collect like terms by subtracting coefficients:
3√6 - 4√6
(3-4)√6
2) calculate (3-4):
(3-4)√6
-1√6
3) the coefficient of -1 does not have to be written, but the negative sign remains:
-1√6
-√6
so therefore:
-√6 is your answer
Answer:
Ok, as i understand it:
for a point P = (x, y)
The values of x and y can be randomly chosen from the set {1, 2, ..., 10}
We want to find the probability that the point P lies on the second quadrant:
First, what type of points are located in the second quadrant?
We should have a value negative for x, and positive for y.
But in our set; {1, 2, ..., 10}, we have only positive values.
So x can not be negative, this means that the point can never be on the second quadrant.
So the probability is 0.
