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Schach [20]
3 years ago
11

Shaelin travels 60 miles per hour with her family for 45 minutes. What is the total distance that her family travels?

Mathematics
1 answer:
Triss [41]3 years ago
3 0
45 miles because 45 minutes is 3/4 of an hour. So to find how many miles they travelled at 60 miles per hour, you need to multiply 60 by 3/4. One way to do that is to divide 60 by 4 which is equal to 15 then multiply 15 by 3 which is equal to 45 miles. 
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Suppose 244 subjects are treated with a drug that is used to treat pain and 51 of them developed nausea. Use a 0.01 significance
vodka [1.7K]

Answer:

z=\frac{0.209 -0.2}{\sqrt{\frac{0.2(1-0.2)}{244}}}=0.351  

p_v =P(z>0.351)=0.363  

So the p value obtained was a very high value and using the significance level given \alpha=0.01 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 1% of significance the proportion of subjects with nauseas is not higher than 0.2 or 20% at 1% of significance.

Step-by-step explanation:

Data given and notation  

n=244 represent the random sample taken

X=51 represent the subjects with nausea

\hat p=\frac{51}{244}=0.209 estimated proportion of subjects with nausea

p_o=0.2 is the value that we want to test

\alpha=0.01 represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion is higher than 0.2.:  

Null hypothesis:p \leq 0.2  

Alternative hypothesis:p > 0.2  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.209 -0.2}{\sqrt{\frac{0.2(1-0.2)}{244}}}=0.351  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.01. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(z>0.351)=0.363  

So the p value obtained was a very high value and using the significance level given \alpha=0.01 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 1% of significance the proportion of subjects with nauseas is not higher than 0.2 or 20% at 1% of significance.

6 0
3 years ago
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Answer:

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Step-by-step explanation:

there are two red pens and 10 black pens. that ratio would be 2/10, or 1/5

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Hunter-Best [27]

Answer:

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Step-by-step explanation:

By definition: 30% = 30/100 = 0.3

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Answer:

w more infor

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Step-by-step explanation:

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Answer:

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