Answer:
3 fish a 2 fish b
Step-by-step explanation:
The formula required is tangent
Solution:
Original Population of elk= 1537
Population after a year =1537 × 1.076
Let rate at which Population of elk is increasing = R %
Let In the beginning the population of elk= P
t= Time after which population is to be found
E(x)=Population of elk after time t,that is E(0)=P
So, Writing the formula at the rate which population of elk is increasing:
⇒E(x)= 
E(1)= 1537
⇒1537= 
1537= 
E(2)= 1537 × 1.076=1653.812
⇒ 1653.812= 

E(9)= 1537 
As P is population when t=0, so we have to find population after 9 years , as
is population when t=1,so considering
as initial population, so, t=8
E(9)= 
= 1537 × 1.796
= 2761.6716
= 2761.68 (Approx)
To solve this first you need to do distributive property, so 2/3(9×-12)=8+2x will now become 6x-12=8+2x because 9 times 2/3 is 18/3 and if you simplify that it will equal to 6, now your new equation will be 6×-12=8+2×. Now you add 12 from both sides and your new equation will be 6x=20+2×,After that you subtract 2x from both sides and your new equation will be 4x=20 and then the last and final thing you do is just divide 20 by 4 and your final answer will be x=5 or 5, hope this helped
Answer:
64
Step-by-step explanation:
6.4 * 10^1
is the same as:
6.4 * 10
= 64