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fgiga [73]
3 years ago
15

A hydrocarbon contains 92.3 grams of carbon and the rest is hydrogen. Calculate its empirical formula and molecular formula. (Mr

= 78)
Chemistry
1 answer:
mote1985 [20]3 years ago
3 0

To find the Empirical Formula and Empirical Formula:

First note down the percentages of the elements in the given compound.

Here, as the compound is a hydrocarbon, we know it involves Carbon and Hydrogen bonded to each other.

Carbon's atomic mass = 12

Hydrogen's atomic mass = 1.008

The compound contains 92.3g of Carbon. It implies it has;

mass of hydrogen = 100 - 92.3 = 7.7g

To find the no.of gram atoms of an element we divide the percentage mass by atomic mass of the said element.

no. of gram atoms of Carbon =  92.3/12 = 7.6916 gram atoms of Carbon

Similarly for Hydrogen,

no. of gram atoms of hydrogen = 7.7/1.008 = 7.63 gram atoms of Hydrogen

Divide all the value of gram atoms by the smallest value among them.

Thus, to determine ratios:

7.69/7.63 = 1.008

Carbon and Hydrogen are in 1:1 ratio.

The ratio between number of atoms gives us the empirical formula. Hence, empirical formula of given compound is: CH.

Molecular mass of a compound = n(empirical formula mass)

Empirical Formula mass = (12 * 1 ) + (1.008 * 1) = 13.008

Molecular mass is given in the question. Therefore, the equation becomes:

78 = n(13.008)

n = 78/13.008

n = 5.99 ≅  6

Therefore, the molecular formula of the given hydrocarbon is: C₆ H₆


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<span>atomic weights: Al = 26.98, Cl = 35.45 In this reaction; 2Al = 53.96 and 3Cl2 = 212.7 Ratio of Al:Cl = 53.96/212.7 = 0.2537 that is approximately four times the mass Cl is needed. Step 2: (a) Ratio of Al:Cl = 2.70/4.05 = 0.6667 since the ratio is greater than 0.2537 the divisor which is Cl is not big enough to give a smaller ratio equal to 0.2537. so Cl is limiting (b)since Cl is the limiting reactant 4.05g will be used to determine the mass of AlCl3 that can be produced. From Step 1: 212.7g of Cl will produce 266.66g AlCl3 212.7g = 266.66g 4.05g = x x = 5.08g of AlCl3 can be produced (c) Al:Cl = 0.2537 Al:Cl = Al:4.05 = 0.2537 mass of Al used in reaction = 4.05 x 0.2537 = 1.027g Excess reactant = 2.70 - 1.027 = 1.67g King Leo · 9 years ago</span>
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5 0
3 years ago
S + 6 HNO3 H2SO4 + 6 NO2 + 2 H2O
exis [7]

Answer:

              101.50 g H₂O

Explanation:

The mole ratio of HNO₃ and H₂O is 6 : 2

Hence, 16.9 moles of HNO₃ will produce = 2/6×16.9 = 5.63 moles of H₂O

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Mass = Moles × M.Mass

Mass = 5.63 mol × 18.02 g/mol

Mass = 101.50 g H₂O

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Electrons in conductors, like copper wire, are free to roam throughout the metal in the presence of the ions that have released
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Metal is not a state of matter. Metals can be solid or liquid (molten) depending on their melting point and the temperature at which they are.

Plasma is a state of matter, similar to gas, but it is reached only at very high temperatures like in the Sun. The particles in plasma state are not neutral atoms or molecules but negatively charged  ions and electrons.

The copper wire is yet a solid, thus it cannot be considered a plasma.

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5 0
3 years ago
A certain electrolyte solution contains 1 gram of salt for every 8 grams of sugar and every 200 grams of water. If the sugar to
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Answer:

The resulting solution contains approximately 666 g of water.

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In the initial solution we have:

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This means that the ratios are:

\frac{salt}{sugar}  = \frac{1}{8} \\\\\frac{sugar}{water} = \frac{8}{200} =\frac{1}{25}

In the final solution we have:

5g salt: xg sugar: yg water

The new ratios are:

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Now we can calculate the amount of sugar in the final solution:

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Finally, we calculate the amount of water:

\frac{sugar}{water} = \frac{13.333}{y} = \frac{1}{50} \\y = 666.667 g

4 0
3 years ago
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