Answer:
Explanation:
Use one of your experimentally determined values of k, the activation energy you determined, and the Arrhenius equation to calculate the value of the rate constant at 25 °C. Alternatively, you can simply extrapolate the straight line plot of ln(k) vs. 1/T in your notebook to 1/298 , read off the value of ln(k), and determine the value of k. Please put your answer in scientific notation. slope=-12070, Ea=100kJ/mol, k= 0.000717(45C), 0.00284(55C), 0.00492(65C), 0.0165(75C), 0.0396(85C)
Explanation;
According to Arrhenius equation:
i.e. ln(k2/k1) = -Ea/R (1/T2 - 1/T1)
Where, k1 = 0.000717, T1 = 45 oC = (45+273) K = 318 K
T2 = 25 oC = (25 + 273) K = 298 K
i.e. ln(k2/0.000717) = -12070 (1/298 - 1/318)
i.e. ln(k2/0.000717) = -2.54738
i.e. k2/0.000717 = 
= 0.078286
Therefore, the required constant (k2) = 0.078286 * 0.000717 = 
Answer:

Explanation:
When you form a <em>diluted solution</em> from a mother (concentrated) solution, the moles of solute are determined by the mother solution.
The main equation is:

Then, since the moles of solute is the same for both the mother solution and the diluted solution:

Substitute and solve for the molarity of the diluted solution:

Answer:
B. Consists of many cells
Explanation:
Unicellular organisms consist of one singular cell. While multicellular organisms consist of many cells
<u>Answer: </u><em>B. Adding more protons to a positively charged body until the number of protons matches the number of electrons</em>
Option B is the appropriate response
<u>Explanation:</u>
Utilising the equivalent number of inverse charges will kill a charged body.
Adding more protons to a decidedly charged body until the number of protons coordinates the quantity of electrons won't kill the body since protons are emphatically charged particles. Adding more protons to an emphatically charged body would make it all the more decidedly charged.
Enabling free electrons to escape from a contrarily charged body will kill since the more negative body leaves the negative electrons.