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3 years ago

Whetes the most of the mass of our solar system today

Chemistry

1 answer:

Simora [160]3 years ago

3 0

Planets, black wholes gravity

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A mixture of propane and butane is burned with pure oxygen. The combustion products contain 46.7 mole% H2O. After all the water

wlad13 [49]

Answer:

28%

Explanation:

Basically, all o did was write the equations, balance it and solve for them. Also, at the place I stared, I used simultaneous equation to solve it. Multiplying by 8 and also 3.

It's a pretty straightforward question.

At the final step that's missing, I Did

(y)C3H8 = 2.8 / ( 2.8 + 7.1)

(y)C3H8 = 0.28

5 0

3 years ago

Which of the following are true of phases?Check all that apply.A.The particles in a liquid are in a fixed location.B.Gases have

saw5 [17]

Answer:

The answers are options b , c and d.

Hope this helps.

7 0

3 years ago

Its Accelerated Science 8th grade

skelet666 [1.2K]

In my opinion I believe it would be motion because depending on how fast the person is going it would determine the outcome of the race

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2 years ago

Many people avoid processed food to eliminate unnecessary ingredients like food dyes and excess sodium from their diets. A study

kvv77 [185]

It should be the answer b but I’m not to sure

4 0

3 years ago

Elimination of the pharmaceutical IV antibiotic gentamicin follows first-order kinetics. If the half-life of gentamicin is 1.5 h

Genrish500 [490]

Explanation:

The given data is:

The half-life of gentamicin is 1.5 hrs.

The reaction follows first-order kinetics.

The initial concentration of the reactants is 8.4 x 10-5 M.

The concentration of reactant after 8 hrs can be calculated as shown below:

The formula of the half-life of the first-order reaction is:

$k=\frac{0.693}{t_1_/_2}$

Where k = rate constant

t1/2=half-life

So, the rate constant k value is:

$k=\frac{0.693}{1.5 hrs}$

The expression for the rate constant is :

$k=\frac{2.303}{t} log \frac{initial concentration}{concentration after time "t"}$

Substitute the given values and the k value in this formula to get the concentration of the reactant after time 8 hrs is shown below:

$\frac{0.693}{1.5 hrs} =\frac{2.303}{8 hrs} x log \frac{8.4x10^-^5}{y} \\ log \frac{8.4x10^-^5}{y} =1.604\\\frac{8.4x10^-^5}{y}=10^1^.^6^0^4\\\frac{8.4x10^-^5}{y}=40.18\\y=\frac{8.4x10^-^5}{40.18} \\=>y=2.09x10^-^6$

Answer: The concentration of reactant remains after 8 hours is 2.09x10^-6M.

5 0

3 years ago