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In-s [12.5K]
3 years ago
15

Whetes the most of the mass of our solar system today

Chemistry
1 answer:
Simora [160]3 years ago
3 0
Planets, black wholes gravity
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You are given a 1.50 g mixture of sodium nitrate and sodium chloride. you dissolve this mixture into 100. ml of water and then a
Elanso [62]

When AgNO₃ solution is added to mixture of NaNO₃ and NaCl, it reacts with NaCl and gives precipitate of AgCl, which is white solid. The reaction takes place in 1:1 stoicheometric ratio as per the following balanced reaction:

NaCl + AgNO₃→ AgCl ↓ + NaNO₃. As per reaction 1 mole NaCl reacts with 1 mole AgNO₃ and gives  of solid precipitate of 1 mole AgCl.

0.641 g= \frac{0.641}{143.32}= 4.47 X 10^{-3} mole of solid AgCl is produced. This indicates 4.47 X 10^{-3} mole NaCl =4.47 X 10^{-3}X58.5 g of Nacl reacts to give 0.641 g of AgCl. So, mass percentage of NaCl present in mixture=\frac{0.26}{1.5} X 100= 17.33 %.

3 0
3 years ago
23 grams of sodium reacts with 293 cm 3 of water that is initially at 298 k. it produces an enthalpy change of 197 kj. what is t
m_a_m_a [10]

448 K is the final temperature of the water.

<h3>What is specific heat capacity?</h3>

The specific heat capacity is defined as the quantity of heat (J) absorbed per unit mass (kg) of the material when its temperature increases by 1 K (or 1 °C), and its units are J/(kg K) or J/(kg °C).

Given,

the mass of Na is 23 g

The volume of water = 293 cm3

Mass of water = 293 g

Total solution mass = 23 g + 293 g = 316 g

Specific heat capacity of water = 4.18 J/Kg

The equation relating mass, heat, specific heat capacity and temperature change is:

q = mcΔT

197 kJ = 316 g x 4.18 J/Kg x (T_{finals} - T_ {initial})

197 kJ = 316 g x 4.18 J/Kg x ( T_{finals}-298 K)

0.1491429956 x 1000 =  T_{finals}-298 K

149.1429956 + 298 = T_{finals}

447.1429956 = T_{finals}

448 K = T_{finals}

Hence, 448 K is the final temperature of the water.

<h3>What does a high specific heat capacity mean?</h3>

A high specific heat capacity means that it can store a large amount of thermal energy for a small change in mass or temperature.

Learn more about specific heat capacity here:

brainly.com/question/2530523

#SPJ4

5 0
2 years ago
If an atom or ion has an atomic number of 3, 2 electrons, and the electronic configuration is 2, what is the mass number? ​
rjkz [21]
It’s mass number would be 5 as it’s the protons and the neutrons added together
7 0
3 years ago
A scientist measures the speed of sound in a monatomic gas to be 449 m/s at 20∘C. What is the molar mass of this gas?
Ivan

Answer:

The molar mass of the gas is 36.25 g/mol.

Explanation:

  • To solve this problem, we can use the mathematical relation:

ν = \sqrt{3RT/M}

Where, ν is the speed of light in a gas <em>(ν = 449 m/s)</em>,

R is the universal gas constant <em>(R = 8.314 J/mol.K)</em>,

T is the temperature of the gas in Kelvin <em>(T = 20 °C + 273 = 293 K)</em>,

M is the molar mass of the gas in <em>(Kg/mol)</em>.

ν = \sqrt{3RT/M}

(449 m/s) = √ (3(8.314 J/mol.K) (293 K) / M,

<em>by squaring the two sides:</em>

(449 m/s)² = (3 (8.314 J/mol.K) (293 K)) / M,

∴ M = (3 (8.314 J/mol.K) (293 K) / (449 m/s)² = 7308.006 / 201601 = 0.03625 Kg/mol.

<em>∴ The molar mass of the gas is 36.25 g/mol.</em>


7 0
3 years ago
Sodium peroxide (Na2O2) is often used in self-contained breathing devices, such as those used in fire emergencies, because it re
Anastaziya [24]

Answer:

725.15 L

Explanation:

The balanced chemical equation for the reaction between Na₂O₂ and CO₂ is the following:

Na₂O₂ + CO₂ → Na₂CO₃ + 1/2 O₂

From the stoichiometry of the reaction, 1 mol of Na₂O₂ reacts with 1 mol CO₂. So, the stoichiometric ratio is 1 mol Na₂O₂/1 CO₂.

Now, we convert the mass of reactants to moles by using the molecular weight (Mw) of each compound:

Mw (Na₂O₂) = (23 g/mol x 2) + (16 g/mol x 2) = 78 g/mol

moles Na₂O₂ = 96.7 g/(78 g/mol) = 1.24 mol Na₂O₂

Mw (CO₂) = 12 g/mol + (16 g/mol x 2) = 44 g/mol

moles CO₂ = 0.0755 g/(44 g/mol) = 1.71 x 10⁻³ mol CO₂

Now, we calculate the number of moles of CO₂ we need to completely react with the mass of Na₂O₂ we have:

1.24 mol Na₂O₂ x 1 mol CO₂/1 mol Na₂O₂ = 1.24 mol CO₂

In 1 L of respired air we have 1.71 x 10⁻³ mol CO₂ (0.0755 g), so we need the following number of liters to have 1.24 mol of CO₂:

1.24 mol CO₂ x 1 L/1.71 x 10⁻³ mol CO₂ = 725.15 L

4 0
3 years ago
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