2sinxcosx - sin(2x)cos(2x) = 0
<span>Part I </span>
<span>The double angle identity for sine states that sin(2x) = 2sinxcosx </span>
<span>Thus we get: </span>
<span>sin(2x) - sin(2x)cos(2x) = 0 </span>
<span>Part II </span>
<span>sin(2x)(1 - cos(2x)) = 0 </span>
<span>Part III </span>
<span>Either sin(2x) = 0 or </span>
<span>1 - cos(2x) = 0 </span>
<span>=> cos(2x) = 1 </span>
<span>For sin(2x) = 0, this is true for </span>
<span>2x = n(pi) where n = 0, 1, 2, .... </span>
<span>x = n(pi/2) </span>
<span>For cos(2x) = 1, this is true for </span>
<span>2x = n(pi) where n = 0, 2, 4, .... </span>
<span>x = n(pi/2)
</span>
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Answer:



Step-by-step explanation:
Given

See comment for complete question
Required
The number of decimal places
To do this, we simply calculate the number of digits after the decimal points


The product is the sum of the digits above 2 + 1 = 3
Hence:

Answer:
29520728184915396206153835295
Step-by-step explanation:
In the recursive formula an = an−1 + 5

Suppose if a_5 is the nth term then previous term is a_4
To get the previous term we need to subtract 1 from the n
So a_n is the nth term
is the previous term
Here 5 represents the common difference between two terms
So value of previous term is represented by

Answer : 