Which is a property of every heterogeneous mixture?

Physics

2 answers:

Masja [62]3 years ago

6 0

Answer: D. The characteristics of the mixture change within a sample.

Explanation: Homogeneous mixture are those mixtures in which dispersed phase is uniformly distributed throughout the dispersion medium and thus the composition is same throughout. There is no physical distinction between the dispersed phase and dispersion medium. Example: Salt in water

Heterogeneous mixture are those mixtures in which dispersed phase is not uniformly distributed throughout the dispersion medium and thus the composition is not same throughout .There is a physical distinction between the dispersed phase and dispersion medium. Example : Oil in water

Aneli [31]3 years ago

3 0

D i am pretty sure :)

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4 years ago

A woman with mass 50 kg is standing on the rim of a large disk that is rotating at 0.80 rev/s about an axis through its center.

My name is Ann [436]

Answer:

angular momentum, $L=1.4\times 10^4\ kg-m^2/s$

Explanation:

Given that,

Mass of the woman, m = 50 kg

Angular velocity of the disk, $\omega=0.8\ rev/s=5.02\ rad/s$

Mass of the disk, m' = 2670 kg

Radius of the disk, R = 4 m

We need to find the magnitude of the total angular momentum of the woman–disk system. The moment of inertia of the system is equal to the sum of moment of inertia of women and the moment off inertia of the disk.

$I=mR^2+\dfrac{1}{2}m'R^2\\\\I=R^2(m+\dfrac{1}{2}m')\\\\I=(4)^2\times (50+\dfrac{1}{2}\times 270)\\\\I=2960\ kg-m^2$

The angular momentum is given by :

$L=I\omega\\\\L=2960\times 5.02\\\\L=14859.2\ kg-m^2/s$

$L=1.4\times 10^4\ kg-m^2/s$

So, the magnitude of the total angular momentum of the woman–disk system is $1.4\times 10^4\ kg-m^2/s$ . Hence, this is the required solution.