3 years ago

Need help on 11 and 13! Please help!

Mathematics

1 answer:

emmasim [6.3K]3 years ago

7 0

Answer:

The answer to question 11 is 10 problems.

The answer to question 13 is 300 students.

You might be interested in

There are 8 times as many females as males on the maths course at university. What fraction

Serga [27]

Answer:

8/9 of the course are males.

4 0

3 years ago

so the volume is that of a cylinder V=hpir^2 h=8 r=2 pi=3.141592 V=8*3.141592*2^2 V=8*3.141592*4 V=32*3.141592 V=100.530944 roun

Mashcka [7]

Volume=(height)(pi)(radius^2)
Volume=(8)(3.141592)(2^2)
V=(8)(4)(3.141592)
V=(32)(3.141592)
V=100.530944

7 0

3 years ago

Dhruv is at a car dealership. He is going to randomly select a vehicle to test drive. There are

andrew-mc [135]

Answer:

P(compact cars) = 4/25

Step-by-step explanation:

We know that there are 13 trucks, 8 vans, and 4 compact cars.

Let P denotes the probability of an event

Now we are asked to find the probability of compact cars

Number of favorable events = number of compact cars = 4

total number of outcomes = 13+8+4 = 25

hence, P(compact cars) = number of favorable events/total outcomes

=4/25

8 0

2 years ago

Plz help meee Thank you very much for whoever helps

ratelena [41]

Answer:

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Prove that sinxtanx=1/cosx - cosx

maks197457 [2]

Answer:

See below

Step-by-step explanation:

We want to prove that

$\sin(x)\tan(x) = \dfrac{1}{\cos(x)} - \cos(x), \forall x \in\mathbb{R}$

Taking the RHS, note

$\dfrac{1}{\cos(x)} - \cos(x) = \dfrac{1}{\cos(x)} - \dfrac{\cos(x) \cos(x)}{\cos(x)} = \dfrac{1-\cos^2(x)}{\cos(x)}$

Remember that

$\sin^2(x) + \cos^2(x) =1 \implies 1- \cos^2(x) =\sin^2(x)$

Therefore,

$\dfrac{1-\cos^2(x)}{\cos(x)} = \dfrac{\sin^2(x)}{\cos(x)} = \dfrac{\sin(x)\sin(x)}{\cos(x)}$

Once

$\dfrac{\sin(x)}{\cos(x)} = \tan(x)$

Then,

$\dfrac{\sin(x)\sin(x)}{\cos(x)} = \sin(x)\tan(x)$

Hence, it is proved

5 0

3 years ago