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nlexa [21]
3 years ago
9

Pedro deposited $7,350 into a savings account 21 years ago. The account has an interest rate of 4.5% and the balance is currentl

y $18,810.67. How often does the interest compound?
Mathematics
1 answer:
Licemer1 [7]3 years ago
5 0
The interest is compounded quarterly because the formula is
A=p (1+r/k)^kt
A it's 18810.67 but I will assume it's unknown ?
P present value 7350
R interest rate 0.045
K compounded quarterly 4
Now solve the formula as the interest is compoundedquarterly
A=7,350×(1+0.045÷4)^(4×21)
A=18,810.67

So the answer is quarterly
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-4(x+1)-3=-3(x-4) solve for x please. Giving brainliest
Sophie [7]

Answer:

-19 = x

Step-by-step explanation:

Step 1: Write equation

-4(x + 1) - 3 = -3(x - 4)

Step 2: Solve for <em>x</em>

<u>Distribute:</u> -4x - 4 - 3 = -3x + 12

<u>Combine like terms:</u> -4x - 7 = -3x + 12

<u>Add 4x on both sides:</u> -7 = x + 12

<u>Subtract 12 on both sides:</u> -19 = x

4 0
3 years ago
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What is y= |x + 5| -4
krek1111 [17]

Answer: n = -9 x2 = -1

Step-by-step explanation:

i might be wrong idk that what i got for my answer

7 0
3 years ago
A parabola has its vertex at (2, 1) and crosses the x-axis at (1,0) anu al l
Y_Kistochka [10]

Answer:

A

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Here (h, k) = (2, 1), thus

y = a(x - 2)² + 1

To find a substitute (1, 0) into the equation

0 = a(1 - 2)² + 1

0 = a + 1 ( subtract 1 from both sides )

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Hence

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y = 1 - (x - 2)² → A

7 0
3 years ago
Situation:
Nat2105 [25]

Answer:

{ \bf{A=(P +  \frac{r}{100} ) {}^{n} }} \\ { \tt{ = (4000 +  \frac{5.5}{100} ) {}^{15} }} \\  \\ { \tt{ =  \: 1.074 \times  {10}^{54}  \: dollars}}

3 0
2 years ago
Match each graph with its corresponding equation
s344n2d4d5 [400]
The equation of the parabolas given will be found as follows:
a] general form of the parabolas is:
y=k(ax^2+bx+c)
taking to points form the first graph say (2,-2) (3,2), thus
y=k(x-2)(x-3)
y=k(x^2-5x+6)

taking another point (-1,5) 
5=k((-1)^2-5(-1)+6)
5=k(1+5+6)
5=12k
k=5/12
thus the equation will be:
y=5/12(x^2-5x+6)

b] Using the vertex form of the quadratic equations:
y=a(x-h)^2+k
where (h,k) is the vertex
from the graph, the vertex is hence: (-2,1)
thus the equation will be:
y=a(x+2)^2+1
taking the point say (0,3) and solving for a
3=a(0+2)^2+1
3=4a+1
a=1/2
hence the equation will be:
y=1/2(x+2)^2+1


5 0
3 years ago
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