We are given
v = 18 m/hr west
θ1 = 285°
θ2 = 340°
After 1 hours, the distance traveled by the ship is
dv = 18 mi
The distance between the ship and the lighthouse is
d = 18 / cos 340
Solve for d<span />
30(-2/5)²(5/8) = 30*(4/25)*(5/8) = 30*4/(5*8) = 3
Answer: 95-4x<40+5x
Step-by-step explanation:
x is the amount of hours per day the water is added to the tank and the question is when will the first tank be less than the second tank so the sign would say less than
Hope this helps :)