Question

Recall Elmer Trett, who in 1994 reached a speed of 103m/s on his motorcycle. Suppose trett drives off a horizontal ramp at this velocity and lands a horizontal distance of 40.0m away from the edge of the ramp. What is the height of ramp?

Answer 1

Speed of the motor cycle is given as

$v_x = 103 m/s$

distance that he moved off from the ramp is given as

$x = 40 m$

now we know that

$x = v_x * t$

$40 = 103* t$

$t = 0.39 s$

now we can use this to find the height

$h = v_i*t + \frac{1}{2}gt^2$

$h = 0 + \frac{1}{2}*9.8*0.39^2$

$h = 0.74 m$

so its height will be 75 cm from ground