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kramer
4 years ago
13

WILL MARK BRAINLIEST!

Physics
1 answer:
boyakko [2]4 years ago
6 0
It’s mass is 100 kg, because if you divide both numbers, you get 100
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Two circular loops carry identical currents, but the radius of one loop is twice that of the other.
Valentin [98]

The magnetic field at the center of the 2nd loop is half the magnetic field at the center of the 1st loop.

Explanation:

The magnetic field strength at the center of a current-carrying circular loop is

B=\frac{\mu_0 I}{2R}

where

\mu_0 is the vacuum permeability

I is the current

R is the radius of the loop

For the first circular loop, we have

B_1 = \frac{\mu_0 I_1}{2R_1}

The second loop has

I_2 = I_1 (same current)

R_2 = 2R_1 (twice the radius)

So, the magnetic field at the centre of the second loop is

B_2 = \frac{\mu_0 I_2}{2R_2}=\frac{1}{2}(\frac{\mu_0 I_1}{2R_1})=\frac{B_1}{2}

So, the magnetic field at the center of the 2nd loop is half the magnetic field at the center of the 1st loop.

Learn more about magnetic fields:

brainly.com/question/3874443

brainly.com/question/4240735

#LearnwithBrainly

4 0
3 years ago
a proton of mass 1 u travelling with a speed of 3.6 x 10 ^4 m/s has an elastic head on collision with a helium nucleus initially
CaHeK987 [17]

Answer:

Velocity of the helium nuleus  = 1.44x10⁴m/s

Velocity of the proton = 2.16x10⁴m/s

Explanation:

From the conservation of linear momentum of the proton collision with the He nucleus:

P_{1i} + P_{2i} = P_{1f} + P_{2f] (1)

<em>where P_{1i}: is the proton linear momentum initial, P_{2i}: is the helium nucleus linear momentum initial, P_{1f}: is the proton linear momentum final, P_{2f}: is the helium nucleus linear momentum final </em>

<u>From (1):</u>

m_{1}v_{1i} + 0 = m_{1}v_{1f} + m_{2}v_{2f} (2)

<em>where m₁ and m₂: are the proton and helium mass, respectively, v_{1i} and v_{2i}: are the proton and helium nucleus velocities, respectively, before the collision, and v_{1f} and v_{2f}: are the proton and helium nucleus velocities, respectively, after the collision </em>

By conservation of energy, we have:

K_{1i} + K_{2i} = K_{1f} + K_{2f} (3)

<em>where K_{1i} and  K_{2i}: are the kinetic energy for the proton and helium, respectively, before the colission, and K_{1f} and  K_{2f}: are the kinetic energy for the proton and helium, respectively, after the colission </em>

<u>From (3):</u>

\frac{1}{2}m_{1}v_{1i}^{2} + 0 = \frac{1}{2}m_{1}v_{1f}^{2} + \frac{1}{2}m_{2}v_{2f}^{2} (4)  

<u>Now we have two equations: (2) ad (4), and two incognits: v_{1f} and v_{2f}. </u>

Solving equation (2) for v_{1f}, we have:

v_{1f} = v_{1i} -\frac{m_{2}}{m_{1}} v_{2f} (5)

<u>From getting (5) into (4) we can obtain the v_{2f}:</u>

v_{2f}^{2} \cdot (\frac{m_{2}^{2}}{m_{1}} + m_{2}) - 2v_{2f}v_{1i}m_{2} = 0

v_{2f}^{2} \cdot (\frac{(4u)^{2}}{1u} + 4u) - v_{2f}\cdot 2 \cdot 3.6 \cdot 10^{4} \cdot 4u = 0

From solving the quadratic equation, we can calculate the velocity of the helium nucleus after the collision:

v_{2f} = 1.44 \cdot 10^{4} \frac{m}{s} (6)

Now, by introducing (6) into (5) we get the proton velocity after the collision:

v_{1f} = 3.6 \cdot 10^{4} -\frac{4u}{1u} \cdot 1.44 \cdot 10^{4}

v_{1f} = -2.16 \cdot 10^{4} \frac{m}{s}

The negative sign means that the proton is moving in the opposite direction after the collision.

I hope it helps you!

7 0
4 years ago
Identifying Applications of Electromagnetic Waves
Anuta_ua [19.1K]

Answer:

gamma ray-destruction of cancer cells

Ultraviolet wave-disruption of DNA

X-ray-diagnosis of illnesses through medical

Explanation: on edg

4 0
3 years ago
How high up is a 3 kg object that has 300 joules of energy
kvasek [131]

Answer:

Height, h = 10.20 meters

Explanation:

It is given that,

Mass of the object, m = 3 kg

Energy of object, E = 300 J

Let it will moved to a height of h. The energy possessed by it is called gravitational potential energy. It is given by :

E=mgh

h=\dfrac{E}{mg}

h=\dfrac{300\ J}{3\ kg\times 9.8\ m/s^2}

h = 10.20 meters

So, the object will move to height of 10.20 meters. Hence, this is the required solution.

5 0
4 years ago
Read 2 more answers
The food calorie, equal to 4186 J, is a measure of how much energy is released when food is metabolized by the body. A certain b
d1i1m1o1n [39]
It’s definitely gonna be A
5 0
3 years ago
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