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kramer
3 years ago
13

WILL MARK BRAINLIEST!

Physics
1 answer:
boyakko [2]3 years ago
6 0
It’s mass is 100 kg, because if you divide both numbers, you get 100
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Jaime lifts a package weighing 75N. if she lifts it 1.2 m, what work has she done
9966 [12]
Answer:
90 J
Explanation:
W=fd
W=(75)(1.2)
W= 90 J
6 0
3 years ago
T or F. A virtual image can sometimes be seen on a screen; it just depends on the situation.
irga5000 [103]
It would be completely false to state that a <span>virtual image can sometimes be seen on a screen; it just depends on the situation. A virtual image can never be seen on a screen. The correct option among the two options that are given in the question is the second option. I hope the answer has come to your help.</span>
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4 years ago
The parents of a new baby believe they brought the wrong child home from the hospital. Gel electrophoresis was performed using D
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Would you be able to post the gel electrophoresis results?
7 0
3 years ago
In order to increase the amount of work completed, it is necessary to decrease the force applied to an object. decrease the time
wlad13 [49]
<span> <span> The answer to your question is: increase the force applied to the object.

Two items are provided as a basis for that conclusion:
1. According to Newton's Second Law of Motion, the formula for finding force is: F = ma
where F is the force,
m is the mass of an object,
and a is the acceleration of the object.

And 2: work = force x distance or W = F x d.</span></span>
5 0
3 years ago
Read 2 more answers
A box of mass 26 kg is initially at rest on a flat floor. The coefficient of kinetic friction between the box and the floor is 0
Kazeer [188]

Answer:

\Delta K = 52J

Explanation:

The change in kinetic energy will be simply the difference between the final and initial kinetic energies: \Delta K=K_f-K_i

We know that the formula for the kinetic energy for an object is:

K=\frac{mv^2}{2}

where <em>m </em>is the mass of the object and <em>v</em> its velocity.

For our case then we have:

\Delta K = K_f-K_i=\frac{mv_f^2}{2}-\frac{mv_i^2}{2}=\frac{m(v_f^2-v_i^2)}{2}

Which for our values is:

\Delta K = \frac{m(v_f^2-v_i^2)}{2} = \frac{(26Kg)((2m/s)^2-(0m/s)^2)}{2} = 52J

3 0
4 years ago
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