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2 years ago

The jet stream occurs in the mesosphere. Please select the best answer from the choices provided T F

Physics

2 answers:

mash [69]2 years ago

7 0

<h2>Answer:</h2>

False:

<h2>Explanation:</h2>

Jet streams are like rivers of wind high above in the atmosphere which have a huge influence on climate because they can push air masses and affect weather patterns. Jet streams travel in the tropopause which is the boundary between the turbulent troposphere and the calm, cold stratosphere. So we can say that jet streams lie in stratosphere and not in mesosphere.

ipn [44]2 years ago

5 0

Answer:

False:

Explanation:

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3 years ago

A fly travels along the x-axis. His starting point is x = 16 m and his ending point 15x = - 25 m. His flight lasts 4.0 seconds H

gogolik [260]

Explanation:

Starting position at x = 16m

Ending position at x = -25m

Time of flight = 4s

Unknown:

Distance flown = ?

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Speed = ?

Velocity = ?

Solution:

To find the distance flown, we should understand that the body is moving on the x - plane;

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2 years ago

Which sentences describe the cyclone device?

Yakvenalex [24]

Answer:

✓ A cyclone device accumulates fine particulates from the air by making a dirty air stream flow in a spiral path inside a cylindrical chamber.

✘ It consists of several long and narrow fabric filter bags suspended upside-down in a large enclosure.

✓ When dirty air enters the chamber, the larger particulates strike the chamber wall and fall into a conical dust hopper at the bottom.

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✓ The top of the chamber has an outlet that lets out cleaned air.

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2 years ago

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umka21 [38]

He must travel 35 mph

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2 years ago

Ten identical steel wires have equal lengths L and equal "spring constants" k. The wires are connected end to end so that the re

lapo4ka [179]

Answer:

$K_{system} = \frac{k}{10}$

Explanation:

When the springs are connected end to end, it means they are connected in series. When the springs are connected in series, the stress applied to the system gets applied to each of the springs without any change in magnitude while the strain of the system is the sum total of strains of each spring. The spring constant of the resultant system is given as,

$\frac{1}{K_{system}} = (\frac{1}{K_{1}})+(\frac{1}{K_{2}})+(\frac{1}{K_{3}})+ (\frac{1}{K_{4}})+.....+(\frac{1}{K_{n}})$

Here, n = 10

Spring constant of each spring = k

Thus,

$\frac{1}{K_{system}} = (\frac{1}{K_{1}})+(\frac{1}{K_{2}})+(\frac{1}{K_{3}})+ (\frac{1}{K_{4}})+.....+(\frac{1}{K_{10}})$

$\frac{1}{K_{system}} = (\frac{1}{k})+(\frac{1}{k})+(\frac{1}{k})+(\frac{1}{k})+(\frac{1}{k})+(\frac{1}{k})+(\frac{1}{k})+(\frac{1}{k})+(\frac{1}{k})+(\frac{1}{k})$

$\frac{1}{K_{system}} = \frac{10}{k}$

$K_{system} = \frac{k}{10}$

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3 years ago

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