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Andre45 [30]
3 years ago
7

Find each of these values.

Mathematics
1 answer:
podryga [215]3 years ago
4 0
192=4\cdot41+28\iff192\equiv28\pmod{41}
28=3\cdot9+1\iff28\equiv1\pmod9

323=24\cdot13+11\iff323\equiv11\pmod{13}
11^2\equiv0\pmod{11}

73=3\cdot23+4\iff73\equiv4\pmod{23}
4^2\equiv16\pmod{31}

212=14\cdot15+2\iff212\equiv2\pmod{15}
2^3\equiv8\pmod{22}
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Answer:

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Step-by-step explanation:

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8 0
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A number is totally even if all its digits are even. For instance, the numbers 2022 is totally even. How many four-digit totally
dem82 [27]

Answer:

The units digit of our number should be and can be any of 0, 2, 4, 6  (four opportunities).

The tens  digit of our number should be and can be any of 0, 2, 4, 6  (four opportunities).

The hundreds digit of our number should be and can be any of 0, 2, 4, 6, 8  (five opportunities).

The thousands digit of our number should be and can be any of 2, 4, 6  (three opportunities).

So, there are 4*4*5*3 = 16*15 = 240  such 4-digits totally even numbers, satisfying the condition.     ANSWER

Step-by-step explanation:

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