Answer:
Measure of angle 1 is 60° and angle 2 is 30°.
Step-by-step explanation:
Let us assume Conrad drew two angles ∠1 = x and ∠2 = y.
Now we go through the question.
Three times the measure of angle 1 is 30 more than 5 times the measure of angle 2.
Now we form the equation 3x = 30+5y
⇒ 3x-5y = 30---------(1)
Again the question says,the sum of twice the measure of angle 1 and twice the measure of angle two is 180.
We form the equation again.
⇒ 2x+2y = 180
2(x+y) = 180
Now we divide the equation by 2 on both the sides
⇒ x+y = 90-------(2)
we multiply equation (2) by 5.
⇒ 5(x+y) = 5×90 = 450
⇒ 5x+5y =450---------(3)
Now we add equation (1) and equation (3)
(3x-5y)+(5x+5y)=30+450
3x-5y+5x+5y =480
8x =480
x = 480÷8 = 60
Now we put the value of x in equation (2)
⇒ 60+y =90
⇒ y = 90-60 = 30
So the angle 1 is 60 and angle 2 is 30.
The first step to solving this is to write 7x as a difference
x² + 9x - 2x - 18
next you need to factor out x from the expression
x × (x + 9) - 2x - 18
then you'll need to factor out -2 from the expression
x × (x + 9) - 2 (x + 9)
lastly,, you need to factor out x + 9 from the expression
(x + 9) × (x - 2)
this means that the correct answer to your question is (x + 9) × (x - 2).
let me know if you have any further questions
:)
Answer:
1- 5xy³√5y
2- 2xy²∛3y²
Step-by-step explanation:
√125x²y^7=
√25*5x²y^6y
5xy³√5y
2) ∛24x³y^8=
∛2³*3x³y^8=
2xy²∛3y²
