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cricket20 [7]
2 years ago
8

Slope of 9 passes through the point (-3,2)

Mathematics
1 answer:
boyakko [2]2 years ago
7 0

Answer:

y-2=9(x+3)

Step-by-step explanation:

y-y1=m(x-x1)

y-2=9(x-(-3))

y-2=9(x+3)

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Expand and simplify 4(2x +7) – 3(x + 5)
Vikentia [17]

Answer:

4\left(2x+7\right)-3\left(x+5\right)=5x+13

Step-by-step explanation:

Given the expression

4\left(2x+7\right)-3\left(x+5\right)

<u>Expand and simplify the expression</u>

4\left(2x+7\right)-3\left(x+5\right)

Expand  4(2x + 7) = 8x + 28                  

4\left(2x+7\right)-3\left(x+5\right)=8x+28-3\left(x+5\right)

Expand  -3(x + 5) = -3x - 15

                                 =8x+28-3x-15

Group like terms

                                  =8x-3x+28-15

Add similar elements:  8x - 3x = 5x

                                   =5x+28-15

Simplify

                                    =5x+13

Therefore, we conclude that:

4\left(2x+7\right)-3\left(x+5\right)=5x+13

6 0
3 years ago
Help please . will give brainliest ​
marishachu [46]

Answer:

A

Step-by-step explanation:

the last number is the y intercept so the intercept in the line is -3.5 so I just matched them up.

3 0
3 years ago
1)cot a/2 -tan a/2 = 2 cot a<br>2) cot b/2 + tan b/2= 2 cosec b<br> prove​
VladimirAG [237]
1)

LHS = cot(a/2) - tan(a/2)

= (1 - tan^2(a/2))/tan(a/2)

= (2-sec^2(a/2))/tan(a/2)

= 2cot(a/2) - cosec(a/2)sec(a/2)

= 2(1+cos(a))/sin(a) - 1/(cos(a/2)sin(a/2))

= 2 (1+cos(a))/sin(a) - 2/sin(a)) (product to sums)

= 2[(1+cos(a) -1)/sin(a)]

=2cot a

= RHS

2.

LHS = cot(b/2) + tan(b/2)

= [1 + tan^2(b/2)]/tan(b/2)

= sec^2(b/2)/tan(b/2)

= 1/sin(b/2)cos(b/2)

using product to sums

= 2/sin(b)

= 2cosec(b)

= RHS
8 0
2 years ago
Find sin A and sec B given a=2 b=11
Sonbull [250]
If there is a triangle with Sid a and b then sina b/✓a2+b2and seven=✓a2+b2/a
7 0
3 years ago
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C=59(F−32)
mestny [16]

Answer: here u go ig

Step-by-step explanation:

4 0
2 years ago
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