Answer : The molecular formula of the compound will be,
Explanation :
Empirical formula : It is the simplest form of the chemical formula which depicts the whole number of atoms of each element present in the compound.
Molecular formula : it is the chemical formula which depicts the actual number of atoms of each element present in the compound.
For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.
The equation used to calculate the valency is :
As we are given that the empirical formula of a compound is and the molar mass of compound is, 90 gram/mol.
The empirical mass of = 1(12) + 2(1) + 1(16) = 30 g/eq
Molecular formula =
Thus, the molecular formula of the compound will be,
The reaction of 1-bromo-2-methylpropane (isobutyl bromide), , with
, and
results in the formation of an adduct of formula
known as grignard reagent, an organometallic reagent, which on reacting with
results in the formation of isobutane.
The reaction is shown in the image.
Answer:
Theoretical yield of HI is 512 g.
The percent yield for this reaction is 25%.
Explanation:
Moles of hydrogen gas = 3.0 moles
Moles of iodine gas = 2.0 moles
According to reaction 1 mol of hydrogen gas reacts with 1 mol of iodine gas.
Then 3.0 moles of hydrogen gas reacts with 3.0 mol of iodine gas. But there are 2.0 moles of iodine gas. Hence,Iodine is a limiting reagent. The production of HI will depend upon iodine gas moles.
According to reaction , 1 mol of iodine gas gives 2 moles of HI.
Then 2 moles of iodine gas will give:
of HI
Theoretically we will get 4 moles of HI.
Theoretical yield of HI = 4 mol × 128 g/mol= 512 g
Experimental yield of HI = 1.0 mol
= 1 mol × 128 g/mol= 128 g
The percent yield for this reaction is 25%.