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drek231 [11]
3 years ago
8

A compound has a molar mass of 90 grams per mole and the empirical formula CH2O. What is the molecular formula of this compound?

Chemistry
2 answers:
Ira Lisetskai [31]3 years ago
8 0
CH2O = 12 + 2 + 16 = 30
90 /30 = 3
3 x (CH2O) = C3H6O3
RSB [31]3 years ago
4 0

Answer : The molecular formula of the compound will be, C_3H_6O_3

Explanation :

Empirical formula : It is the simplest form of the chemical formula which depicts the whole number of atoms of each element present in the compound.  

Molecular formula : it is the chemical formula which depicts the actual number of atoms of each element present in the compound.  

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is :

n=\frac{\text{molecular mass}}{\text{empirical mass}}

As we are given that the empirical formula of a compound is CH_2O and the molar mass of compound is, 90 gram/mol.

The empirical mass of CH_2O = 1(12) + 2(1) + 1(16) = 30 g/eq

n=\frac{\text{molecular mass}}{\text{empirical mass}}

n=\frac{90}{30}=3

Molecular formula = (CH_2O)_n=(CH_2O)_3=C_3H_6O_3

Thus, the molecular formula of the compound will be, C_3H_6O_3

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In a laboratory experiment the reaction of 3.0 mol of H2 with 2.0 mol of I2 produced 1.0 mole of HI. Determine theoratical yield
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The percent yield for this reaction is 25%.

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According to reaction 1 mol of hydrogen gas reacts with 1 mol of iodine gas.

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