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const2013 [10]
3 years ago
8

What organic product would be formed from the reaction of 1-bromo-2-methylpropane (isobutyl bromide), (ch3)2chch2br, with mg, et

2o, then , then h3o+?

Chemistry
1 answer:
miskamm [114]3 years ago
4 0

The reaction of 1-bromo-2-methylpropane (isobutyl bromide), (CH_3)_2CHCH_2Br, with Mg, and Et_2O results in the formation of an adduct of formula (CH_3)_2CHCH_2MgBr known as grignard reagent, an organometallic reagent, which on reacting with H_3O^{+} results in the formation of isobutane.

The reaction is shown in the image.

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  • Answer: <em><u>The compounds containing CFCs (chlorofluorocarbons) are mainly responsible for ozone layer depletion as these compounds react with ozone in the presence of ultraviolet rays to form oxygen molecule and thus, destroying ozone.</u></em>

Explanation: <em><u>Human activities cause the emission of halogen source gases that contain chlorine and bromine atoms. These emissions into the atmosphere ultimately lead to stratospheric ozone depletion. The source gases that contain only carbon, chlorine, and fluorine are called chlo- rofluorocarbons usually abbreviated as CFCs.</u></em>

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3 years ago
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The following reaction has been reported in the chemical literature and gives a single organic product in high yield. Write the
Alla [95]

Answer:

Explanation:

The principle applied is the Markovnikoff's rule which states that when hydrogen chloride adds to a double bond, the hydrogen atoms join to the carbon that already has the most hydrogen atoms bonded to it. The rule wa postulated by a russian chemist known as Vladimir Markovnikoff.

In the markovnikoff's rule, there are sveral conditions that must be met, one of them is that no free radicals must be involved.

The reaction and the structure of the product is as shown in the attachment.

8 0
3 years ago
when two amino acid monomers are positioned so that the carboxyl group of one is adjacent to the amino group of the other, they
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They can be joined through a Peptide bond

The amino acids serve as the foundation for proteins. Water is produced when the amino acids are linked to form a lengthy chain of acids via amino and carboxyl. The main protein is made up of these long chain amino acids.

When the carboxyl group of one molecule combines with the amino group of the other molecule, a molecule of water is released, and a peptide bond is created between the two molecules (H2O). This condensation event, sometimes referred to as a dehydration synthesis reaction, typically takes place between amino acids.

<h3>What is a Peptide bond ?</h3>

The carboxyl group of one amino acid is joined to the amino group of another to produce a peptide bond, also known as a eupeptide bond. In essence, a peptide link is an amide-type covalent chemical bond.

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6 0
1 year ago
What volume of a concentrated HCl solution, which is 36.0% HCl by mass and has a density of 1.179 g/mL, should be used to make 4
Ivenika [448]

Answer:

130ml of HCl(36%) in 4.90L solution => pH = 1.50

Explanation:

Need 4.90L of HCl(aq) solution with pH = 1.5.

Given pH = 1.5 => [H⁺] = 10⁻¹·⁵M = 0.032M in H⁺

[HCl(36%)] ≅ 12M in HCl

(M·V)concentrate = (M·V)diluted

12M·V(conc) = 0.032M·4.91L

=> V(conc) needed = [(0.032)(4.91)/12]Liters = 0.0130Liters or 130 ml.

Mixing Caution => Add 131 ml of HCl(36%) into a small quantity of water (~500ml) then dilute to the mark.

5 0
3 years ago
A chemist mixes 75.0 g of an unknown substance at 96.5°C with 1,150 g of water at 25.0°C. If the final temperature of the system
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To do this problem it is necessary to take into account that the heat given by the unknown substance is equal to the heat absorbed by the water, but considering the correct sign:

-m\cdot c_e\cdot \Delta T = m_w\cdot c_e_w\cdot \Delta T_w

Clearing the specific heat of the unknown substance:

c_e = \frac{m_w\cdot c_e_w\cdot \Delta T_w}{m\cdot \Delta T} = -\frac{1\ 150\ g\cdot 4.184\frac{J}{g\cdot ^\circ C}\cdot (37.1 - 25.0)^\circ C}{75\ g\cdot (37.1 - 96.5)^\circ C}

c_e = -\frac{1\ 150\ g\cdot 4.184\frac{J}{g\cdot ^\circ C}\cdot 12.1^\circ C}{75\ g\cdot (-59.4)^\circ C} = \bf 13.07\frac{J}{g\cdot ^\circ C}
6 0
3 years ago
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