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const2013 [10]
3 years ago
8

What organic product would be formed from the reaction of 1-bromo-2-methylpropane (isobutyl bromide), (ch3)2chch2br, with mg, et

2o, then , then h3o+?

Chemistry
1 answer:
miskamm [114]3 years ago
4 0

The reaction of 1-bromo-2-methylpropane (isobutyl bromide), (CH_3)_2CHCH_2Br, with Mg, and Et_2O results in the formation of an adduct of formula (CH_3)_2CHCH_2MgBr known as grignard reagent, an organometallic reagent, which on reacting with H_3O^{+} results in the formation of isobutane.

The reaction is shown in the image.

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In the ground state, an atom of which element has seven valence
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For the aqueous solution containing 75 mg of compound C in 1.0 mL of water, what will be the total amount of the solute C that w
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Answer:

75 mg

Explanation:

We can write the extraction formula as

x = m/[1 + (1/K)(Vaq/Vo)], where

x = mass extracted

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K = distribution coefficient

Vo = volume of organic layer

Vaq = volume of aqueous layer

Data:

m = 75 mg

K = 1.8

Vo = 0.90 mL

Vaq = 1.00 mL

Calculations:

For each extraction,

1 + (1/K)(Vaq/Vo) = 1  + (1/1.8)(1.00/0.90) = 1 + 0.62 = 1.62  

x = m/1.62 = 0.618m

So, 61.8 % of the solute is extracted in each step.

In other words, 38.2 % of the solute remains.

Let r = the amount remaining after n extractions. Then  

r = m(0.382)^n.

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r = 75(0.382)^7 = 75 × 0.001 18 = 0.088 mg

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After seven extractions, 75 mg (99.999 %) of the solute will be extracted.

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