Question

Determine the concentration of the following dye standard made by a student who pipettes out 2.50 mL of a 0.250 M stock solution and transfers it into a volumetric flask and dilutes the dye to a final volume of 100.0 mL with DI water.

Answer 1

Answer:

Concentration of dye in diluted solution is 0.00625 M

Explanation:

The given problem can be solved by using laws of dilution

According to laws of dilution-   $C_{1}V_{1}=C_{2}V_{2}$

where $C_{1}$ and $C_{2}$ are initial and final concentration respectively

          $V_{1}$ and $V_{2}$ are initial and final volume respectively

Here, $C_{1}=0.250 M$, $V_{1}=2.50mL$ and $V_{2}=100.0mL$

So, $C_{2}=\frac{C_{1}V_{1}}{V_{2}}$

or, $C_{2}=\frac{(0.250M)\times (2.50mL)}{100.0mL}$

or, $C_{2}=0.00625M$

So, concentration of dye in diluted solution is 0.00625 M