All categories

2 years ago

What is the equation of a line that crosses the y axis at (0,-3) and has a slope of 4?

1 answer:

8 0

Hi dear,

use this formula:

y - y1= m(x-x1)

Y1 = -3
X1 = 0
m = 4

y-(-3)=4(x-0)

y+3=4x

y=4x-3

You might be interested in

elena-s [515]

It's a mixed fraction so it would be 1 2/10 and 1 4/100

6 0

3 years ago

kogti [31]

Answer:

Whats up

Step-by-step explanation:

6 0

3 years ago

vfiekz [6]

Answer:

no pictur no answer

Step-by-step explanation:

8 0

2 years ago

LekaFEV [45]

Answer: $y-1=\dfrac32(x+3)$

Step-by-step explanation:

Slope of a line passes through (a,b) and (c,d) = $\dfrac{d-b}{c-a}$

In graph(below) given line is passing through (-2,-4) and (2,2) .

Slope of the given line passing through (-2,-4) and (2,2) = $\dfrac{-4-2}{-2-2}=\dfrac{-6}{-4}=\dfrac{3}{2}$

Since parallel lines have equal slope . That means slope of the required line would be .

Equation of a line passing through (a,b) and has slope m is given by :_

(y-b)=m(x-a)

Then, Equation of a line passing through(-3, 1) and has slope = is given by

$(y-1)=\dfrac32(x-(-3))\\\\\Rightarrow\ y-1=\dfrac32(x+3)$

Required equation: $y-1=\dfrac32(x+3)$

8 0

2 years ago

ratelena [41]

Answer:

depends mostly it'll b 180 degress

Step-by-step explanation:

4 0

1 year ago