If the 5 scores have a mean of 8, then their total sum would be 8*5 = 40
Now if one score if added (let's call this score x), there are 6 scores and the mean changes to 9, thus:
(40 + x)/6 = 9
40 + x = 54
x = 14
To find the surface area of any object, the first step that you must do is find all shapes that are present in the object.
Here we have 2 triangles and 3 rectangles.
Knowing this, simply find the area of each shape.
Since the triangles are the same, one is facing up and the other down, they both would be 15.6 cm^2.
The rectangles would be 54 cm^2. as there are 3 ( 6 x 3 cm) ones.
Add the values up to have the surface area.
It’s 85.2 cm^2.
Since LM = AM, point M must be on the perpendicular bisector of AL. Since AM = BM, BL must be perpendicular to AL. This makes ∆ALC a right triangle with hypotenuse AC twice the length of side AL. Hence ∠LAC = ∠LAB = 60°, and AL is angle bisector, median, and altitude.
ΔABC is isosceles with ∠A = 120°, and ∠B = ∠C = 30°.
For two complex numbers
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and

, the product is
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That is, you multiply the moduli and add the arguments. You have

and

, so the product is