Answer:
The measure of arc BD is 147°
Step-by-step explanation:
we know that
If segment AB is perpendicular to segment CD
then
The measure of the inner angle CPA is a right angle (90 degrees)
Remember that
The measure of the inner angle is the semi-sum of the arcs comprising it and its opposite.
so
m∠CPA=(1/2)[arc AC+arc BD]
substitute the given values
90°=(1/2)[33°+arc BD]
180°=33°+arc BD
arc BD=180°-33°=147°
Answer:
ok so lets find what percentage 630 is of 3050
630/3050=0.20655737704
so about 20.7%
Hope This Helps!!!
Answer:
um... you are wrong
Step-by-step explanation:
its the the last one
you can't add when its division
you can change exponents from 1/x^-2
to x^2
<h2>
<em><u>I nweed brainliest</u></em></h2>
Let's define variables:
s = original speed
s + 12 = faster speed
The time for the half of the route is:
60 / s
The time for the second half of the route is:
60 / (s + 12)
The equation for the time of the trip is:
60 / s + 60 / (s + 12) + 1/6 = 120 / s
Where,
1/6: held up for 10 minutes (in hours).
Rewriting the equation we have:
6s (60) + s (s + 12) = 60 * 6 (s + 12)
360s + s ^ 2 + 12s = 360s + 4320
s ^ 2 + 12s = 4320
s ^ 2 + 12s - 4320 = 0
We factor the equation:
(s + 72) (s-60) = 0
We take the positive root so that the problem makes physical sense.
s = 60 Km / h
Answer:
The original speed of the train before it was held up is:
s = 60 Km / h
B agree
A,c, d don’t make sense
