<em>If this guy doesn't use the letter m, then the first and second characters of the password could be any of the 25 remaining letters. So, the number of possible combinations of 2 letters is 25 times 25, or 625.
If he doesn't use the digit 0, how many digits are left to choose from?
The first 2 characters of the password will be letters; after that there come four digits. How many different combinations of 4 digits are there if 0 is not used?
To obtain the final result, mult. together that 625 and the number of possible combinations of digits just found above.</em>
Answer:
according to writer it answer is 2 minute
An obtuse triangle must have an angle greater than 90degrees (cannot equal 90). Therefore, A. would be the correct answer. This is because A. is the only set of angles that includes an angle greater than 90. Also, all angle measures add up to equal 180degrees.
Part 1 -
1. f(x) = 5(x-2)^2 + 4
axis of symmetry: x = 2
vertex: (2, 4)
2. f(x) = 12(x + 6)^2 - 5
axis of symmetry: x = -6
vertex: (-6, -5)
3. f(x) = 2x^2 + 8x - 7
axis of symmetry: x = -2
vertex: (-2, -15)
I have to go somewhere right now, but I will get back to you as soon as I can (probably within a couple of hours) to finish answering the rest of your questions.
400,000 + 6,000 + 500 + 100 = 406,600
That is
Four hundred six thousand six hundred.
