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Darina [25.2K]
3 years ago
11

the lateral area of a right circular cone is 20pi cm^2 and the total area is 36pi cm^2 find the volume of the cone

Mathematics
2 answers:
Lady bird [3.3K]3 years ago
8 0
Let r = radius, h = height and l = slant height 

Lateral area = rlpi 

But l = sqrt(r^2 + h^2) 

Lateral area = r sqrt( r^2 + h^2) pi = 20 pi..................(1) 

Total area = r sqrt( r^2 + h^2) pi + r^2 pi = 36pi......(2) 

Subtract (1) from (2) 

r^2 pi = 16 pi 

r^2 = 16 

r = 4 cm 

Put this value in (1) to find h 

4sqrt(4^2 + h^2) pi = 20 pi 

sqrt(16 + h^2) = 5 

Square both sides 

16 + h^2 = 25 

h^2 = 9 

h = 3 cm 

Now that we know h and r we can find the volume 


V = 1/3 pi r^2 h 

= 1/3 pi (4^2)(3) 

<span>= 16 pi cm^3 .........( = 50.27 cm^3)

I hope my answer has come to your help. God bless and have a nice day ahead!
</span>
Alina [70]3 years ago
8 0
Hello there.
<span>
The lateral area of a right circular cone is 20pi cm^2 and the total area is 36pi cm^2 find the volume of the cone
</span>
 50.27 cm^3

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52 × 2 - 31 = 73

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Use PEMDAS

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6 0
3 years ago
We learned in that about 69.7% of 18-20 year olds consumed alcoholic beverages in 2008. We now consider a random sample of fifty
maw [93]

Answer:

(1) The expected number of people who would have consumed alcoholic beverages is 34.9.

(2) The standard deviation of people who would have consumed alcoholic beverages is 10.56.

(3) It is surprising that there were 45 or more people who have consumed alcoholic beverages.

Step-by-step explanation:

Let <em>X</em> = number of adults between 18 to 20 years consumed alcoholic beverages in 2008.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.697.

A random sample of <em>n</em> = 50 adults in the age group 18 - 20 years is selected.

An adult, in the age group 18 - 20 years, consuming alcohol is independent of the others.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 50 and <em>p</em> = 0.697.

The probability mass function of a Binomial random variable <em>X</em> is:

P(X=x)={50\choose x}0.697^{x}(1-0.697)^{50-x};\ x=0,1,2,3...

(1)

Compute the expected value of <em>X</em> as follows:

E(X)=np\\=50\times 0.697\\=34.85\\\approx34.9

Thus, the expected number of people who would have consumed alcoholic beverages is 34.9.

(2)

Compute the standard deviation of <em>X</em> as follows:

SD(X)=\sqrt{np(1-p)}=\sqrt{50\times 0.697\times (1-0.697)}=10.55955\approx10.56

Thus, the standard deviation of people who would have consumed alcoholic beverages is 10.56.

(3)

Compute the probability of <em>X</em> ≥ 45 as follows:

P (<em>X</em> ≥ 45) = P (X = 45) + P (X = 46) + ... + P (X = 50)

                =\sum\limits^{50}_{x=45} {50\choose x}0.697^{x}(1-0.697)^{50-x}\\=0.0005+0.0001+0.00002+0.000003+0+0\\=0.000623\\\approx0.0006

The probability that 45 or more have consumed alcoholic beverages is 0.0006.

An unusual or surprising event is an event that has a very low probability of success, i.e. <em>p</em> < 0.05.

The probability of 45 or more have consumed alcoholic beverages is 0.0006. This probability value is very small.

Thus, it is surprising that there were 45 or more people who have consumed alcoholic beverages.

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