$\displaystyle\\(x-4)^2=49\\\\(x-4)^2-49=0\\\\(x-4)^2-7^2=0\\\\(x-4-7)(x-4+7)=0\\\\(x-11)(x+3)=0\\\\x-11 = 0~~~\text{or}~~~x+3=0\\\\x-11=0~~~\implies~~~\boxed{x_1=11}\\\\x+3=0~~~\implies~~~\boxed{x_2=-3}\\\\\boxed{\bf The~solutions~are:~~x =11~~\text{or}~~x =-3}$

8 0

2 years ago

On the first day of your garage sale, you earned 12x+9 dollars. The next day you earned 22x dollars. Is it possible you earned t

Mrac [35]

No, no value for x will result in you getting the same amount of money
I.e. on the first day if x =2 you earn 33. on the second day you would've earned 44. Of course this may be wrong so best to double check

4 0

2 years ago

(6x+1/2)+(2x-8 1/2)Simplify the expression.

ella [17]

Answer:

simplified = 8x - 8

Step-by-step explanation:

trust me :)

7 0

2 years ago

Question 7 of 10

Nat2105 [25]

Answer:

D. Balloon Mortgage does not adjust each period

Step-by-step explanation:

A-P-E-X

5 0

2 years ago

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