Answer:
A. 3.4 m
Explanation:
Given the following data;
Force = 56.7N
Workdone = 195J
To find the distance
Workdone is given by the formula;
Making "distance" the subject of formula, we have;
Substituting into the equation, we have;
Distance = 3.4 meters.
Answer:
option B
Explanation:
given,
spring constant (k ) = 45 N/m
distance of the spring = 0.8 m
Magnitude of the force to handle grip = ?
Magnitude of spring force =
F = k x
F = 45 x 0.8
F = 36 N
The magnitude of spring force is equal to F = 36 N
The correct answer is option B
Answer:A
Explanation:
In R-L circuit current is given by
where i=current at any time t
R=resistance
L=Inductance
at t=0 approaches to 1
therefore
i=0
when t approaches to , approaches to zero
thus
thus we can say that initially circuit act as broken wire with zero current
and it increases exponentially with time and act as ordinary connecting wire
-- 4.5 minutes lasts 270 seconds
-- the case covers 15m in each sec
-- its total distance is
(15 m/s) x (270 sec) = 4,050 meters
Answer:
3160.41J
Explanation:
From the work energy theorem, the net work done is given by;
W = Kef - Keo
Where kef is final kinetic energy and keo is initial kinetic energy.
Now, from the question,
m = 62.8 kg
Initial speed(vo) = 5.2 m/s
Final speed (vf) = 11.3 m/s
We know that formula for kinetic energy is K = (1/2)mv²
Thus, Kef = (1/2)mvf² and Keo = (1/2)mvo²
Thus;
W = (1/2)mvf² - (1/2)mvo²
W = (m/2)(vf² - vo²)
W = (62.8/2)(11.3²-5.2²)
= 31.4(100.65) = 3160.41J