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2 years ago

A major league baseball has a mass of 0.145 kg.

Physics

1 answer:

galben [10]2 years ago

6 0

The momentum of the ball when it hits the ground is 4.89 kg.m/s.

The given parameters;

<em>mass of the baseball, m = 0.145 kg</em>
<em>height of fall of the ball, h = 58 m</em>

The final velocity of the ball when it hits the ground is calculated as follows;

$v_f ^2 = v_0^2 + 2gh\\\\v_f^2 = 0 + 2gh\\\\v_f^2 = 2gh\\\\v_f = \sqrt{2gh} \\\\v_f = \sqrt{2\times 9.8 \times 58}\\\\v_f = 33.72 \ m/s$

The momentum of the ball when it hits the ground is calculated as follows;

P = mv

P = 0.145 x 33.72

P = 4.89 kg.m/s

Thus, the momentum of the ball when it hits the ground is 4.89 kg.m/s.

Learn more here:brainly.com/question/22035809

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If you stood on a planet with four times the mass of Earth, and twice Earth's radius, how much would you weigh?

nikdorinn [45]

Answer:

1/4 times your earth's weight

Explanation:

assuming the Mass of earth = M

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∴ the mass of the planet= 4M

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3 years ago

A flywheel with radius of 0.400 mm starts from rest and accelerates with a constant angular acceleration of 0.600 rad/s2rad/s2.

charle [14.2K]

Answer: $0.00024\ m/s^2$

Explanation:

Given

Radius of flywheel is $r=0.4\ mm$

Angular acceleration $\alpha=0.6\ rad/s^2$

For no change in radius, tangential acceleration is given as

$\Rightarrow a_t=a\lpha \times r$

Insert the values

$\Rightarrow a_t=0.6\times 0.4\times 10^{-3}\ m/s^2\\\Rightarrow a_t=2.4\times 10^{-4}\ m/s^2\ \text{or}\ 0.00024\ m/s^2$

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3 years ago

A motorcycle accelerated from 10 metre per second to 30 metre per second in 6 seconds. How far did it travel in this time ?

Ber [7]

U=10 m/s
v=30 m/s
t=6 sec

therefore, a=(v-u)/t
=(30-10)/6
=(10/3) ms^-2

now, displacement=ut+0.5*a*t^2
=60+ 0.5*(10/3)*36
=120 m
And you can solve it in another way:

v^2=u^2+2as
or, s=(v^2-u^2)/2a
=(900-100)/6.6666666.......
=120 m

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3 years ago