What is the correct order of increasing electronegativity? 1. f, o, n, c, s, p, si 2. si, p, s, c, n, o, f 3. o, c, n, s, p, si,
f 4. f, si, p, s, n, c, o?
1 answer:
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Answer:
Option C.
Step-by-step explanation:
Total population = 1000 snails
AA = 160 snails
Aa = 480 snails
aa = 360 snails
Frequency of each type.
Now, we get
he frequency of the A allele in this population is 0.4.
Therefore, the correct option is C.