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Vesna [10]
2 years ago
13

I’m confused on this

Mathematics
1 answer:
Karolina [17]2 years ago
6 0
The answer is 12.  theorem- in the above figure if bf is a perpendicular to ca then cf and fa are congruent                

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How do I solve this problem about reflection?
marishachu [46]
F should be -1, 6
E should be -4, 2
D should be -4, 9
4 0
2 years ago
Are these ratios equivalent?
masya89 [10]

Answer:

A, yes.

Step-by-step explanation:

63:60, 21:20:

The difference between 60 and 20 is *3. If you do that to 21, you get 63. So a , yes.

3 0
2 years ago
Help with a,b,c answers
Ket [755]
The answers For A,B,C.
A.2
B.2.25
C.1
6 0
2 years ago
Find the difference in the given lengths of the polygons . (7x + 2) units (6x - 5) units .
Tom [10]

Answer:

Difference in the lengths of the polygons is (x + 7) units.

Step-by-step explanation:

Lengths of the given polygon = (7x + 2) units and (6x - 5) units

Therefore, difference in the given lengths = (7x + 2) - (6x - 5)

                                                                      = (7x - 6x) + (2 + 5)

                                                                      = x + 7

Therefore, difference in the lengths of the polygons is (x + 7) units.

7 0
2 years ago
What is the sum of the numbers in the series? 15 + 11 + 7 + . . . + (–129)
babymother [125]
Using Gauss's method
Total number of terms = [15-(-129)]/4+1=36+1=37
Add
S=15+11+7+....-125-129
S=-129-125-...+7+11+15
--------------------------------
2S=-114-114-114...(37 times)
=>
sum=S=(1/2)*(-114)*37=-2109


Using AP, T(n)=15+11+7+....-129
T(n)=19-4n  => T(1)=15, T(37)=-129
S(n)=(1/2)(37)(T(1)+T(37)=(1/2)37(15-129)=2109
3 0
2 years ago
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