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Oxana [17]
4 years ago
6

I NEED HELP ASAP!!!!!!!!!!!!

Physics
1 answer:
OLga [1]4 years ago
4 0

Answer:

Since S (displacement) = v * t

you can calculate the area under the graph

S = 1/2 * 3 * 15 - 3 * 13 = 22.5 - 39 = -16.5 m

In the triangular area the object travels at an average speed of 7.5 m/s

for 3 sec = 22.5 m

In the rectangular area the object travels at an average speed of -3 m/s

for 13 sec = -39 m.

So the net distance traveled is 22.5 - 39 = -16.5 m

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Mary is driving a car of mass 900 kilograms toward the north with a velocity of
lorasvet [3.4K]
Since both cars move together after the collision, then this is an example of an inelastic collision. The formula for an inelastic collision is as follows:

m1u1 + m2u2 = (m1 + m2)v

Where:

m1 = mass of the first object
m2 = mass of the second object
u1 = initial velocity of the first object
u2 = initial velocity of the second object
v = final velocity

Substituting the given values to solve for v:

900*22 + 900*15 = (900 + 900)v
v = 18.5 m/s
3 0
4 years ago
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Which is the force of repulsion between two positivity-charged particles?
Yuki888 [10]

Since they are both positively charged, then the force would in fact be repulsion, because they are both the same. If you were to have one positively charged, and one negatively charged, then they would go towards eachother.

I hope this helps, if you need help on this question or any other questions, just ask. I am here to help.

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3 years ago
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A string that is restricted at both ends has a length of 1.50 m. what is the wavelength of the string’s fundamental frequency?
lara31 [8.8K]
Since it is restricted at both ends, λ/2 = length of string

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6 0
3 years ago
Two forces are acting on an object as shown in Fig. on the right. What is the magnitude of the resultant force?
svetlana [45]

Answer:

185 N

Explanation:

Sum of forces in the x direction:

Fₓ = -(80 N cos 75°) + (120 N cos 60°)

Fₓ = 39.3 N

Sum of forces in the y direction:

Fᵧ = (80 N sin 75°) + (120 N sin 60°)

Fᵧ = 181.2 N

The magnitude of the net force is:

F = √(Fₓ² + Fᵧ²)

F = √((39.3 N)² + (181.2 N)²)

F = 185 N

8 0
3 years ago
Distance in scientific notation
n200080 [17]

Answer:

(See explanation for further information)

Explanation:

a) The distances of each planet with respect to the Sun is:

Mercury - 57.909 \times 10^{6}\,mi

Venus - 67.240\times 10^{6}\,mi

Earth - 92.960\times 10^{6}\,mi

Mars - 141.600\times 10^{6}\,mi

Jupiter - 483.800\times 10^{6}\,mi

Saturn - 888.200\times 10^{6}\,mi

Uranus - 1,787\times 10^{6}\,mi

Neptune - 2,795\times 10^{6}\,mi

b) The solutions are presented below:

A. The distance between Venus and Jupiter is:

\Delta s = 483.800\times 10^{6}\,mi-67.240\times 10^{6}\,mi

\Delta s = 416.560\times 10^{6}\,mi

B. The combined distance from the Sun is:

\Delta s = 57.909\times 10^{6}\,mi + 67.240\times 10^{6}\,mi +92.960\times 10^{6}\,mi

\Delta s = 218.109\times 10^{6}\,mi

Which is less than the distance from the Sun to Neptune (2,795\times 10^{6}\,mi).

C. The new distance of Earth is 929.60 \times 10^{6}\,mi (929,600,000\,mi). Saturn would be the closest planet to Earth, whose distance:

Scientific notation:

\Delta s = 929.600\times 10^{6}\,mi-888.200\,\times 10^{6}\,mi

\Delta s = 41.4\times 10^{6}\,mi

Standard notation:

\Delta s = 929,600,000\,mi - 888,200,000\,mi

\Delta s = 41,400.000\,mi

3 0
4 years ago
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