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sertanlavr [38]
3 years ago
10

A scientist compares two samples of white powder. One powder was present at the beginning of an experiment. The other powder was

present at the end. She wants to determine whether a chemical reaction has occurred. She finds that neither sample bubbles or dissolves in water. She measures the mass and volume of the solids. Sample one has a volume of 45 cm3 and a mass of 0.5 g. Sample two has a volume of 65 cm3 and a mass of 1.3 g. What should the scientist conclude?
A)The samples have the same color, so no chemical reaction has occurred.
B)The two samples do not react with water, so no chemical reaction has occurred.
C)The densities of the samples are different, so a chemical reaction has occurred.
D)The densities of the samples are the same, so no chemical reaction has occurred.
E)The densities of the samples are different, so no chemical reaction has occurred.
Physics
1 answer:
Jet001 [13]3 years ago
4 0
Density of powder 1 = 0.5 g / 45 cm^3 = 1/90 g/cm^3
Density of powder 2 = 1.3 g / 65 cm^3 = 1/50 g/cm^3

Therefore the densities of the two powders are different, hence chemical reaction has occurred.

(note: none of the other choices make sense.  In fact, a different density does not necessarily indicate a chemical change, see paragraph below).

Density of powders are not definitive unless they are each of the same size and texture.  For example, granular sugar, rock sugar, and icing sugar all have different densities.  I would conclude that this experiment does not lend to a reliable answer.
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The air inside a balloon exerts a force of 1.5 n on an area of 0.5 m^2. what is the pressure inside the balloon?
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NASA developed a reflective foil barrier to help shield spacecraft from heat transfer in space. These reflective barriers are no
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Answer: Radiation

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3 0
3 years ago
An electron is initially moving at 1.4 x 107 m/s. It moves 3.5 m in the direction of a uniform electric field of magnitude 120 N
algol13

Answer:

K.E = 15.57 x 10⁻¹⁷ J

Explanation:

First, we find the acceleration of the electron by using the formula of electric field:

E = F/q

F = Eq

but, from Newton's 2nd Law:

F = ma

Comparing both equations, we get:

ma = Eq

a = Eq/m

where,

E = electric field intensity = 120 N/C

q = charge of electron = 1.6 x 10⁻¹⁹ C

m = Mass of electron = 9.1 x 10⁻³¹ kg

Therefore,

a = (120 N/C)(1.6 x 10⁻¹⁹ C)/(9.1 x 10⁻³¹ kg)

a = 2.11 x 10¹³ m/s²

Now, we need to find the final velocity of the electron. Using 3rd equation of motion:

2as = Vf² - Vi²

where,

Vf = Final Velocity = ?

Vi = Initial Velocity = 1.4 x 10⁷ m/s

s = distance = 3.5 m

Therefore,

(2)(2.11 x 10¹³ m/s²)(3.5 m) = Vf² - (1.4 x 10⁷)²

Vf = √(1.477 x 10¹⁴ m²/s² + 1.96 x 10¹⁴ m²/s²)

Vf = 1.85 x 10⁷ m/s

Now, we find the kinetic energy of electron at the end of the motion:

K.E = (0.5)(m)(Vf)²

K.E = (0.5)(9.1 x 10⁻³¹ kg)(1.85 x 10⁷ m/s)²

<u>K.E = 15.57 x 10⁻¹⁷ J</u>

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Explain how balanced and unbalanced forces effect an objects motion differently
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Balanced Forces acting on an object will not change the object's motion. Unbalanced Forces acting on an object will change the change the object's motion.
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