Complete Question:
A chemist adds 55.0 mL of a 1.1M barium acetate (Ba(C2H3O2)2) solution to a reaction flask. Calculate the mass in grams of barium acetate the chemist has added to the flask. Round your answer to 2 significant digits.
Answer:
15 g
Explanation:
The concentration of the barium acetate is given in mol/L (M), thus, the number of moles (n) of it is the concentrantion multiplied by the volume (55.0 mL = 0.055 L):
n = 1.1 * 0.055
n = 0.0605 mol
The molar mass of the substance can be calculated by the sum of the molar mass of each element, which can be found at the periodic table. Thus:
Ba = 137.33 g/mol
C = 12.00 g/mol
H = 1.00 g/mol
O = 16.00 g/mol
Ba(C2H3O2)2 = 137.33 + 4*12 + 6*1 + 4*16 = 255.33 g/mol
The molar mass is the mass divided by the number of moles, thus the mass (m) is the molar mass multiplied by the number of moles.
m = 255.33 * 0.0605
m = 15.45 g
Rounded by 2 significant digits, m = 15 g.
<span>A SI base unit is the single and direct measurement unit for a physical entity. E.g. For mass it is kg, for time it is sec, A derived unit is determined by a physical equation with the base units, like for velocity equals distance divided by time, in SI units: unit of v (velocity)= m (meter) divided by sec (seconds).
Hope this helps!</span>
When salt is added to ice , it comes into contact with the thin layer of water on the surface of the melting ice. ... This salt water has a lower freezing point, so the temperature of the ice bath can get even colder, thus freezing the ice cream more quickly.
Answer:
B.) 2.92
Explanation:
Tp find the mass of H₂ produced, you need to (1) convert grams AlCl₃ to moles AlCl₃ (via molar mass), then (2) convert moles AlCl₃ to moles H₂ (via mole-to-mole ratio from equation coefficients), and then (3) convert moles H₂ to grams H₂ (via molar mass). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units.
Molar Mass (AlCl₃): 26.982 g/mol + 3(35.453 g/mol)
Molar Mass (AlCl₃): 133.341 g/mol
2 Al + 6 HCl ---> 2 AlCl₃ + 3 H₂
Molar Mass (H₂): 2(1.008 g/mol)
Molar Mass (H₂): 2.016 g/mol
129 g AlCl₃ 1 mole 3 moles H₂ 2.016 g
------------------ x ------------------ x --------------------- x --------------- =
133.341 g 2 moles AlCl₃ 1 mole
= 2.93 g H₂
*our answers are most likely different due to using slightly different molar masses
10.3 g of will produce from 12.7 g .
In simple terms, a limiting reagent is a reactant that is completely used up in the reaction.
It is also referred to as a limiting reactant or limiting agent.
Now, according to the question,
Since it is a limiting reagent, it will react fully.
The mass of that will be produced will be:-
Equivalent mole of = Equivalent weight of = 12.7/169.97 = x*2/274x = 10.3 g.
Hence, 10.3 g of will be produced.
It is used to restrict the reaction.
It tells you the estimated amount of compound to be used.
It brings quantitative understanding to chemical reactions.
More information on limiting reagents can be found here :
brainly.com/question/11848702
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