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blsea [12.9K]
3 years ago
14

Hi! Can anybody help me with these problems? I have to do 2 step equations.

Mathematics
2 answers:
Dovator [93]3 years ago
6 0
1) 3.8x + 5.2x - 6.7 = 11.3
9x = 11.3 + 6.7
9x = 18
x = 18/9
x = 2

2) 7.8y - 4.9 - 5.4y = 2.3
2.4y = 7.2
y = 7.2/2.4
y = 3

3)

\frac{2}{3} x - 5 = 1
\frac{2}{3} x = 5 + 1
\frac{2}{3} x = 6

Multiply by 3 by both sides:

3 \times \frac{2}{3} x = 3 \times 6

Simplify:

2x = 18
x = 18/2
x = 9

4)

\frac{7}{5} y = 3 - \frac{1}{5}

Do lowest common denominator:

\frac{7}{5} y = \frac{(5 \times 3) - 1}{5}
\frac{7}{5} y = \frac{15 - 1}{5}
\frac{7}{5} y = \frac{14}{5}

Simplify by 5 by both sides:

7y = 14
y = \frac{14}{7}
y = 2
zzz [600]3 years ago
4 0

Answer:


Step-by-step explanation:

for question number one you want to first combine like terms:

  1.   9x-6.7=11.3  
  2. 9x=18
  3. x=2

for number 2 you should teh smame:

  1. 2.4y-4.9=2.3
  2. 2.4y=7.2

so as long as you combine like terms then proceed to solve you should get the right answers

                                               

   

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So, when x = -10.


If you notice, -10 is NOT in the domain (the domain is (-3,13))

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A chord is 15 cm long. It is 9 cm from the center of the circle. What is the radius of the circle?
irakobra [83]

Answer:

<h2>11.72cm</h2>

Step-by-step explanation:

Given a chord of distance of 15cm, if it is 9cm from the center of a circle, this means that the 9cm length will be projecting from the centre of the circle perpendicular to the chord and passing through its centre.

Since the radius of a circle is a line that is drawn from the centre of a circle to ts circumference, the set up will form a right angles triangle within the circle with the hypotenuse as the radius and the other two sides as the opposite and adjacent respectively. Using the Pythagoras theorem to get the length of the radius (hypotenuse);

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Solve system of equations 2x + 2y + 5z = 7 6x + 8y + 5z = 9 2x + 3y + 5z = 6
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Answer:

the values of x, y and z are x= 2, y =-1 and z=1

Step-by-step explanation:

We need to solve the following system of equations.

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2x + 2y + 5z = 7     eq(1)

6x + 8y + 5z = 9     eq(2)

2x + 3y + 5z = 6     eq(3)

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