Answer:
see explanation below
Step-by-step explanation:
1500 × 3 × 20 ÷ 100
$900
Hello,
function minmax(int p1,int p2,int p3, int adr_big, int adr_small)
{ int mini=p1,maxi=p1;
if (p1>p2) {mini=p2;}
else {maxi=p2;};
if (p3>maxi) maxi=p3;
if (p3<mini) mini=p3;
*adr_big=maxi;
*adr_small=mini;
};
// main
int a=31,b=5,c=19,big,small;
minmax(a,b,c,&big,&small);
Looking at the graph you can see that the domain of the function is:
[0, 3.85]
To find the range of the function, we must follow the following steps:
Step 1)
Evaluate for t = 0
h (0) = - 4.87 (0) ^ 2 + 18.75 (0)
h (0) = 0
Step 2)
find the maximum of the function:
h (t) = - 4.87t ^ 2 + 18.75t
h '(t) = - 9.74 * t + 18.75
-9.74 * t + 18.75 = 0
t = 18.75 / 9.74
t = 1.925051335
We evaluate the function at its maximum point:
h (1.925051335) = - 4.87 * (1.925051335) ^ 2 + 18.75 * (1.925051335)
h (1.93) = 18.05
The range of the function is:
[0, 18.05]
Answer:
Domain: [0, 3.85]
Range: [0, 18.05]
option 1